First, we need to find which number when substituted into the equation will give the answer zero. \(f(1) = {(1)^3} + 4{(1)^2} + (1) - 6 = 0\) Therefore \((x - 1)\)is ...
If a quadratic equation can be factorised, the factors can be used to find the roots of the equation. The equation factorises to give \((x + 3) (x - 2) = 0 \) so the solutions to the equation \(x ...