To construct the tangent to a curve at a certain point A, you draw a line that follows the general ... to remember that all lines and curves that slope upwards have a positive gradient.

We can calculate the gradient of a tangent to a curve by ... into the original equation of the curve to find the y-coordinate Substitute your point on the line and the gradient into \(y - b ...

Does this function have a tangent line with a slope of 20 anywhere on this interval? Explain. Let \(C\) be the curve \(y=(x-1)^3\) and let \(L\) be the line \(3y+x=0\text{.}\) Find the equation of all ...