As a tangent is a straight line it is described by an equation in the form \(y - b = m(x - a)\). You need both a point and the gradient to find its equation. You are usually given the point - it's ...

Find the point(s) on the curve \(y=x^3\) where the line through ... Does this function have a tangent line with a slope of 20 anywhere on this interval? Explain. Let \(C\) be the curve \(y=(x-1)^3\) ...