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Delta potential - Wikipedia
In quantum mechanics the delta potential is a potential well mathematically described by the Dirac delta function - a generalized function. Qualitatively, it corresponds to a potential which is zero …
Bound States in a Double Delta Function Potential [closed]
Let $V(x) = −u \delta(x) - v \delta(x − a)$ where $u, v > 0$ correspond to a potential with two $\delta$ wells. Let $v > u$. If $a$ is very large, there is certainly a bound state: the particle
In the last post we had a look at the bound states of the double delta function potential V(x)= [ (x+a)+ (x a)] (1) where gives the strength of the well. In this post, we’ll look at the scat-tering …
[1603.07726] Revisiting double Dirac delta potential - arXiv.org
2016年3月23日 · We study a general double Dirac delta potential to show that this is the simplest yet versatile solvable potential to introduce double wells, avoided crossings, resonances and …
We study a general double Dirac delta potential to show that this is the simplest yet still versatile solvable potential to introduce double wells, avoided crossings, resonances and perfect …
Particles moving from left encounter d-function potential at x = 0: will either continue moving in +x direction (i.e., they are transmitted through the region of potential change)
Revisiting double Dirac delta potential - ResearchGate
2016年3月23日 · We study a general double Dirac delta potential to show that this is the simplest yet versatile solvable potential to introduce double wells, avoided crossings, resonances and …
What are the real life examples of Double Dirac-Delta Potential …
2017年10月1日 · The strength parameter for the potential is often set by considering the dissociation regime, i.e. imagining that the two nuclei are so far apart that the electron is …
We can extend the case of the particle in a delta function well to the case of a particle in a double delta function well. That is, the potential is V(x)= [ (x+a)+ (x a)] (1) where gives the strength of …
11.2 Delta Potential As an example of how the boundaries can be used to set constants, consider a -function potential well (negative), centered at the origin. For V(x) = (x), we have scattering …