
How do you use the Binomial Theorem to find the value of #99^4#?
2018年5月3日 · How do you use the binomial series to expand #1 / (1+x)^4#? How do you use the binomial series to expand #f(x)=(1+x)^(1/3 )#? See all questions in The Binomial Theorem
Find the sum of the following number sequence: #1+2+3+4+5+6 …
2018年3月7日 · 55 Add the first and the last numbers of the sequence and repeat for the other sets of numbers. 1 + 10 = 11 2 + 9 = 11 3 + 8 = 11 4 +7 = 11 5 + 6 = 11 This gives 5 sets of …
Prove that #1^99+2^99+3^99+4^99+5^99# is divisble by 5.
2018年7月28日 · See proof below 1=1\\mod 5 1^{99}=1^99\\mod 5 1^{99}=1\\mod 5 Similarly, 2^{99}=2^{99}\\mod 5 3^{99}=(-2)^99\\mod 5 4^{99}=(-1)^99\\mod 5 5^{99}=0\\mod 5 …
What is the z score of a 99 confidence interval? - Socratic
2016年3月4日 · 2.576 Z score of a 99 confidence interval is 2.576. The third quartile, denoted #Q_3#, is the data value such that what percent of the values are below it?
What is the molar mass of sulfuric acid H_2SO_4? - Socratic
2017年4月8日 · Sulfuric acid's molar mass is "98.08 g/mol". Step one: Find the atomic masses in each atom -- units: "g/mol" Hydrogen: 1.01 Sulfur: 32.06 Oxygen: 16 Step two: Find how many …
What is the molecular weight of air? - Socratic
2016年8月22日 · If you add these up you get: 78.084 + 20.946 + 0.934 + 0.03 = 99.994% (the remaining material 100 - 99.994 = 0.006% consists of trace amounts of other gases) These …
What volume is occupied by a 64*g mass of oxygen gas ... - Socratic
2017年10月28日 · The molar volume of #"STP"# is usually quoted at #22.4*L*mol^-1# (these definitions vary according to the syllabus you follow.... For the molar quantity of this mass of …
The Standard Normal Distribution - Statistics - Socratic
How do you use the 68-95-99.7 rule to find the percentage of people with scores below 84? If students toss a coin 200 times each, about 68% should have proportions between what two …
The sum of three consecutive odd integers is 99. What are
2016年1月21日 · I found 31,33,35 Let us call our odd integers: 2n+1 2n+3 2n+5 and write our condition as: (2n+1)+(2n+3)+(2n+5)=99 and solve it for n: 6n+9=99 6n=90 n=90/6=15 so our …
Which is a recursive formula for the sequence 99.4, 0, –99
2018年6月27日 · Notice that in our sequence is 0-99.4=-99.4 -99.4-99.4=0 -198.8-99.4=99.4... So we are dealing with an arithmetic sequence with difference -99.4. Each term is build up …