
Why is cos(0) = 1? - Socratic
2015年6月28日 · At #0# degrees, the angle intercepts the Unit Circle at the coordinate #(1,0)#. The coordinates are the trig values. The coordinates are the trig values. The x-coordinate is …
How do you find the exact value of cos^-1 0? - Socratic
2018年6月1日 · see below cos^(-1)0=arccos 0 What is the arc which cosine is zero?: two posibilities 90=pi/2 and 270=3pi/2 This is assuming that cos^(-1) is the inverse of cosine. …
SOLUTION: When does cos(x) = 0? - Algebra Homework Help
From the "unit circle" cos(x)=0 when In terms of degrees: 90 and 270 degrees In terms of radians: (pi)/2 ...
When cosx=0, what does x equal? - Socratic
2016年5月15日 · 90^o x= cos^-1(0) = 90^o Using the cosine graph, x could also = 270^o, 450^o, 810^o, -90^o, -270^o, -450^o, -810^o etc. Trigonometry Science
If cos >0 and sin <0 what quadrant is it in? - Socratic
2016年5月29日 · Consider the rule C-A-S-T or All Slow Turtles Crawl for this type of problem. Both of these rules indicate in which quadrant the trigonometric function is positive. In all …
How do you find the 6 trigonometric functions for 0 degrees?
2015年8月18日 · sin(0^o) = 0color(white)("XXXX")csc(0^o) "undefined" cos(0^o)=1color(white)("XXXX")sec(0^o)=1 tan(0^o)=0color(white)("XXXX")cot(0^o) …
How do you find the value of #cos^ -1(0) - Socratic
2015年10月28日 · cos^{-1}0=pi/2 graph{cosx [-7.855, 7.856, -3.93, 3.925]} cos^{-1} is an angle x, for which cos x=0. If you look at the graph of f(x)=cosx you see that cosx=0 for x=pi/2+kpi for …
How do you solve cosx=0? - Socratic
2016年4月1日 · x=pi/2+kpi, k in ZZ In the trigonometric circle you will notice that cos(x)=0 corresponds to x=pi/2 and also x=-pi/2. Additionally to these all the angles that make a …
How do you solve for x in sin2x+cosx=0? - Socratic
2018年4月5日 · sin 2x + cos x = 0 2sin x.cos x + cos x = 0 cos x(2sin x + 1) = 0 either factor should be zero. a. cos x = 0 Unit circle gives 2 solutions -->
How do you solve cosx+ cos(3x) =0? - Socratic
2017年2月18日 · x = pi/2, (3pi)/2, pi/4, (3pi)/4, (5pi)/4 and (7pi)/4 Note that cos3x can be rewritten as cos(2x + x). cosx + cos(2x + x) = 0 Now use cos(A + B) = cosAcosB - sinAsinB. cosx + …