2018年7月7日 · See explanation. To simplify this expression first let's calculate some low powes of i: i^2=-1 i^3=-i i^4=1 From this calculations we can write that: i^41=i^40*i=(i^4)^10*i=1^10*i=i

2016年11月10日 · Trevon received $12 for cleaning the attic. Since Trevon had 29 on Friday and 41 now after cleaning the attic over the weekend, the amount he received, x, can be …

2015年5月31日 · 33 = (25+41)/2 The average of the terms of a contiguous subsequence of any arithmetic progression is the average of the first and last terms. To see this, notice that if you …

2018年3月7日 · A sample of concentrated nitric acid has a density of 1.41gmL and contains 70.0% HNO3 by mass. (a).what mass of HNO3 per liter of solution?

2016年2月20日 · 5/12 The following is the standard procedure to solve the problem: 0.41bar(6)=0.41+0.00bar(6) if x=0.0066666....: 1000x=6.6666.... and 100x=0.666666 Then, if …

2017年11月1日 · See a solution process below: A composite number is: a whole number that can be divided evenly by numbers other than 1 or itself. Because every even number is divisible by …

2015年9月21日 · Use a Newton Raphson type method to find: sqrt(404.41) ~~ 20.10994779 404.41 = 20^2 + 2.1^2, so you might think there's a nice expression for sqrt(404.41), but not …

2018年3月24日 · #"This is true because the volume of an ideal gas is 22.41 L/mol at STP."# Answer link. Related questions.

2015年8月14日 · 41 You can use PEMDAS to help you simplify this expression. Since you're not dealing with parantheses or exponents, you need to focus on the MDAS part of PEMDAS. In …

2015年7月31日 · The difference between each term and the next is the next odd prime number. Let p_0 = 2, p_1 = 3, p_2 = 5, p_3 = 7,... be the prime numbers.