In the case of the $\ce{N2 + O2 -> 2NO}$ , $\Delta H$ and $\Delta S$ are both positive, so the reaction is thermodynamically favorable at high temperature (such as in lightning) but not at low temperature. If the temperature drops to room temperature after NO is formed, it is thermodynamically favorable for NO to decompose to nitrogen and oxygen.

2020年6月16日 · $$\ce{N2 + O2 -> 2NO}$$ So I know the second reaction is endothermic as we need to break triple bonds between nitrogen molecules. I am not sure about the first one. Actually, I want to know if there is some way we can decide whether a reaction is endothermic or exothermic just by looking at the equation?

2019年7月22日 · I think that it should be F2 because F is smaller than N and O thus having a small bond length. And small bond length means greater energy (my teacher told me). But the answer is N2.

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2024年6月18日 · N,(nitrogen), O (oxygen) and Cu (copper) are all elements. Nitrogen is only found as the gas N2. Oxygen has several molecular forms, including the best known the gas O2. Copper is found as metal.

2022年3月14日 · I was studying Thermodynamics from my Chemistry textbook (page 181-182, section 6.6 (a)). I have a question regarding the following text from my book. Now let us examine the following reactions: $$\\

2022年10月18日 · Since we want to determine the Stoichiometric Mixture of propane from the oxygen reading, I am using 78.08% as N2 and 20.95% as O2 for the calculation which gives the N2/O2 ratio of 3.73. The stoichiometric mixture for propane is 15.67. If using N2/O2 ratio of 3.76, the oxygen level at stoichiometric mixture will be approximately 19.75%.

2024年6月3日 · O2, N2, Cl2, and I2 are examples of diatomic molecules, which consist of two atoms of the same element bonded together. These molecules are stable due to having a full valence shell of electrons ...

2024年6月19日 · H2, N2, O2, F2, Cl2, Br2, and I2. What happens to a gas produced in a reaction? it depends on what is reacting most commonly it is H2 gas or O2 gas or CO2 gas.

2014年7月18日 · This phenomenon is explained by s-p mixing. All the elements in the second period before oxygen have the difference in energy between the 2s and 2p orbital small enough, so that s-p mixing (combination) can occur lowering the energy of the σ(2s) and σ*(2s) and increasing the energy of the σ(2p) and σ*(2p) molecular orbitals.