2020年9月22日 · This question shows research effort; it is useful and clear

2023年4月28日 · I was looking at the STREETSWEEPER Mod when I saw an image of Donnie Darko holding the gun and I wanted the outfit, comments talked about it being in the XHX discord server, and after some digging, I wasn't able to find it, so if anyone has the link or a way to get the link that would be really cool.

2022年12月12日 · This question has most probably been asked so many times in the past so apologies but I can't seem to get any links that actually work. I've read about xhx discord server, is there any way I could get a link to the server or any other options for ports

The reason you are having trouble proving it is that it is not true as stated. For a heavy-handed example, let G G be the free group on x x and y y, and let H H be the subgroup generated by all elements of the form xnyx−n x n y x − n with n> 0 n> 0. Then for any a ∈ H a ∈ H we have xax−1 ∈ H x a x − 1 ∈ H. However, x−1yx ∉ H x − 1 y x ∉ H, because any element of H H is ...

2019年10月2日 · I have already proven that xHx−1 x H x − 1 is a subgroup of G G by showing ∗ ∗ is closed and finding an inverse is closed, but now I need to show xHx−1 x H x − 1 and H H are isomorphic.

2019年1月27日 · No such subgroups exist, since for x = 1 x = 1, we always have xHx−1 = H x H x − 1 = H. So, it is true that xHx−1 ⊊ H x H x − 1 ⊊ H for all x ∈ G x ∈ G implies H H is a normal subgroup, but the implication is vacuous. More strongly, if xHx−1 ⊆ H x H x − 1 ⊆ H for all x ∈ G x ∈ G, then actually xHx−1 = H x H x − 1 = H for all x ∈ G x ∈ G (the inclusion cannot ...

2018年10月1日 · Suppose G is a group. H is a subgroup of G. Now determine whether ∪x ∈ GxHx − 1 is a subgroup. I tend to proof this is not true since I know the union of any two subgroups which do not contained in another is not a subgroup. But I don't know if it is true for countable unions. I need a counterexample such that ∪x ∈ GxHx − 1 is not a subgroup

2023年2月3日 · Is the “Imports From Tarkov” mod gone forever with the removal of invites to xhx’s discord server? Is there no link/file posted anywhere other than the server mentioned? If there’s anyone out there with access to this mod - you would be making a total stranger very happy with his mod list!

2015年1月20日 · Hint: For each x ∈ G, xHx−1 is a subgroup of G. Now show that intersection of (any number of) subgroups is again a subgroup of G. This will prove that N is a subgroup of G. Fix a ∈ G. Now define a function f: G → G, x ↦ ax. This is a bijection. Hence {xHx−1: x ∈ G} = {(ax)H(ax)−1: x ∈ G}. Note: This proof is essentially the one …

2020年6月25日 · It's easy to show N <G, since H is a subgroup of G any conjugate xHx − 1 (x ∈ G) of H is also a subgroup of G, and the intersection of subgroups is also a subgroup.