How do you graph the line y=1? + Example - Socratic
2017年8月3日 · A straight line parallel to the x-axis through the point (0,1) y=1 A straight line in slope (m) and intercept (c) form is: y=mx+c In this example, y is a straight line of slope 0 and y …
How do you graph y=-1? - Socratic
2017年1月29日 · How do you graph #y=-1#? Algebra Graphs of Linear Equations and Functions Graphs Using Slope-Intercept Form.
#y^{'''}-3y^{''}+2y^'=\frac{e^{2x}}{1+e^x}#? - Socratic
2017年12月18日 · Course: Differential Equations with Linear Algebra (don't use Linear Algebra please)
SOLUTION: If y(x-1)=z then x= please help me understand this.
You can put this solution on YOUR website! What the question is asking you to do is to solve for x. This means that you will need to get x on one side of the equation and everything else on …
SOLUTION: how do you graph y=x-1? - Algebra Homework Help
Now mark these two locations on your graph paper. Starting at the origin of your graph (where the x-axis crosses the y-axis), go to the right 2 squares (x=2) then up 1 square (y=1) and mark …
Please help me to solve this by linear inequality? In a graph...
You can put this solution on YOUR website! y > x - 1 Graph the boundary line y = x - 1 Slope-intercept form is y = mx + b
SOLUTION: Graph the solution of y-2>1 on a number line.
You can put this solution on YOUR website! y-2 > 1 y-2+2 > 1+2 y+0 > 3 y > 3 To graph y > 3, you step 1) draw out a number line
How do you verify the identity cot^2y(sec^2y-1)=1? - Socratic
2017年1月17日 · see below Left Hand Side: Use identity :1+tan^2y=sec^2y cot^2y(sec^2y-1)=cot^2ytan^2y =cos y/siny * siny /cos y =cancelcos y/cancelsiny * cancelsiny /cancelcos y …
Asymptotes - Precalculus - Socratic
Let's take the function #y=1/x# graph{1/x [-10, 10, -5, 5]} You will see, that the larger we make #x# the closer #y# will be to #0# but it will never be #0# #(x->oo)# In this case we call the line …
How do you find the inverse of #y=e^(x-1)#? - Socratic
2015年12月6日 · f^(-1)(x) = ln x +1 Given y= e^(x-1) (this is a one-to-one function) Step 1: Switch x for y and y for x like this color(red) x= e^(color(blue)(y)-1) Step 2: Begin to solve for y Take ln …