2015年9月7日 · Using the Pythagorean identity: tan^2x = sec^2x - 1 This is an application of the Pythagorean identities, namely: 1 + tan^2x = sec^2x This can be derived from the standard Pythagorean identity by dividing everything by cos^2x, like so: cos^2x + sin^2x = 1 cos^2x/cos^2x + sin^2x/cos^2x = 1/cos^2x 1 + tan^2x = sec^2x From this identity, we can rearrange the terms to arrive at the answer to your ...

2015年11月2日 · Simplify (sec^2 - 1)/sec^2 Ans: sin^2 x Replace sec^2 = 1/(cos^2 x into the expression , we get: (1/(cos^2 x - 1))/(1/(cos^2 x)) = ((1 - cos^2 x)/cos^2 x)((cos^2 x)/1 ...

2016年8月25日 · #tan^2x+1=sec^2xrArrtan^2x=sec^2x-1# multiply through by -1. #rArr-tan^2x=1-sec^2x# Answer link. Related ...

2017年3月9日 · The numerator is a #color(blue)"difference of squares"# and is factorised, in general, as shown.. #color(red)(bar(ul(|color(white)(2/2)color(black)(a^2-b^2=(a-b)(a+b ...

2017年1月26日 · see below Use the identity: sec x=1/cos x 1/secx=1/(1/cosx)=1*cosx/1=cos x

2016年9月16日 · Using the #color(blue)"trigonometric identity"#. #color(red)(bar(ul(|color(white)(a/a)color(black)(sin^2x+cos^2x=1)color(white)(a/a)|)))#

2018年1月9日 · True Start with the well known pythagorean identity: sin^2x + cos^2x -= 1 This is readily derived directly from the definition of the basic trigonometric functions sin and cos and Pythagoras's Theorem. Divide both side by cos^2x and we get: sin^2x/cos^2x + cos^2x/cos^2x -= 1/cos^2x :. tan^2x + 1 -= sec^2x :. tan^2x -= sec^2x - 1 Confirming that the result is an identity.

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2017年7月12日 · Prove that tan^2 x+1=sec^2x? Trigonometry. 1 Answer Narad T. Jul 12, 2017 ...

2018年3月20日 · See Below Left Hand Side:: sec^2(x)-tan^2x =1/cos^2x -(sin^2x)/cos^2x =(1-sin^2x)/cos^2x =cos^2x/cos^2x-> Use Property sin^2x+cos^2x=1 and isolate cos^2x =cancel(cos^2x/cos^2x =1 = Right Hand Side