You can put this solution on YOUR website! 14.13 x 21.6 =305.208 (using a calculator) . 14.13 X 21.6 _____ ...

Factorising gives (x - 1)(x - 9) = 0 x = 1 and x = 9 give solutions to the equation. With x = 1 we have sides 5, 12 and 13 which is reasonable; but with x = 9 we have sides -3, 4 and 5 which does satisfy the equation but as we are talking about lengths (which are all positive) we disregard this answer. Therefore the sides are 5, 12 and 13 with ...

Looking at we can see that the first term is and the last term is where the coefficients are 5 and -6 respectively. Now multiply the first coefficient 5 and the last coefficient -6 to get -30. Now what two numbers multiply to -30 and add to the middle coefficient -13? Let's list all of the factors of -30: Factors of -30: 1,2,3,5,6,10,15,30

You can put this solution on YOUR website! (x+13)(x-13)(x+7)>0 x+13>0 x>-13 ans. x-13>0 x>13 ans. x+7>0 x>-7 ans. ...

V = length × width × height V = (8-2x)(6-2x)x V = x(8-2x)(6-2x) V = (8x-2x²)(6-2x) V = 48x-16x²-12x²+4x³ V = 4x³-28x²+48x We get some points between 0 and 3: x | y ----- .2 | 8.512 .4 | 14.976 .6 | 19.584 .8 | 22.528 1.0 | 24.0 1.1 | 24.244 1.2 | 24.192 1.3 | 23.868 1.4 | 23.296 1.6 | 21.504 1.8 | 19.008 2.0 | 16.0 2.5 | 7.5 2.9 | 1.276 ...

Question 777580: 8=56 7=42 6=30 5=20 3=? What does 3 equal? Found 8 solutions by oscargut, solver91311, tinbar, nyc_function, gurungsantosh, MathTherapy, acubed1234, mbessearch:

f(x) = x^3-7x^2+25x-39 = (x-3)(x^2-4x+13) That is as far as we can factor without going into complex numbers. x^2-4x+13 has no real zeros, but it has, as expected, two conjugate complex zeros, which we can find using the quadratic formula or completing the square.

c=0.90 , x=13.5 , s=0.77 Algebra -> Probability-and-statistics -> SOLUTION: Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed.

Question 1088915: A population of values has a normal distribution with μ=206.3 and σ=51.5. You intend to draw a random sample of size n=202.

the number of ways you can get 2 kings is c(4,2) = 6 the number of ways you can get 3 other cards is (c(48,3) = 17296. the total number of ways you can get 5 cards where 2 are kings and 3 are something else is 6 * 17296 = 103776. to see how this works, try something a lot simpler. assume the deck has 4 kings and 1 jack and a queen only.