2018年3月19日 · The only number satisfiying this equation is -1 15·(-1)=-15 Other way to do this is transposing terms From 15x=-15 we have x=-15/15=-1 Algebra Science

2018年8月2日 · "see explanation" >"one way is to find the intercepts, that is where the graph" "crosses the x and y axes" • " let x = 0, in the equation for y-intercept" • " let ...

2017年1月19日 · Have a look: Your equation represents a straight line passing through y=15 and with slope 15 (the coefficicient of x). The slope tells you that for each increment of 1 in x then y increases of 15. To graph it you can set: x=0 giving the intercept y=15 and, say... x=1 giving y=15+15=30 whith these two points you have enough informations to plot your line:

2017年10月29日 · look at the following :) As there are brackets, we can first expend those brackets and group the like terms together. 20x+15x+20(x-1)+15(x-1)-245 =20x+15x+20x-20+15x-15-245 =70x-280 I'm not sure if you want to ask the following, but I just write it down in case you need this: When the question is asking 20x+15x+20(x-1)+15(x-1)-245=0 we have the left side in the above, so: 70x-280=0 70x=280 x=4 ...

2016年3月27日 · Find a pair of factors of #56# with sum #15#. The pair #7, 8# works in that #7*8 = 56# and #7+8=15# Hence: #0 = x^2+15x+56 = (x+7)(x+8)# So: #x = -7# or #x = -8# #color(white)()# Alternative method. I will use the difference of squares identity: #a^2-b^2 = (a-b)(a+b)# with #a=(2x+15)# and #b=1# as follows:

2018年3月29日 · (x-7)(x-8) >"consider the factors of + 56 which sum to - 15" "the factors are - 7 and - 8" rArrx^2-15x+56=(x-7)(x-8)

2016年7月15日 · #x(x+15)=0# Because the product is 0, one of the two factors must be equal to 0. Either #x = 0, or x+ 15 =0," in which case " x = -15# This gives two solutions, exactly what we expect with a quadratic.

2016年3月11日 · How do you factor #x^3 + 7x^2 + 15x + 9#? Algebra Polynomials and Factoring Factoring Completely. 1 Answer

2018年1月19日 · Correct answer is (C) 3(5x+1) In all these we use distributive property of numbers, which states that axx(b+c)=axxb+axxc.

2015年6月14日 · #f(x) = 4x^2+15x+10# is of the form #ax^2+bx+c# with #a=4#, #b=15# and #c=10# The discriminant is given by the formula: #Delta = b^2-4ac = 15^2-(4xx4xx10) = 225 - 160 = 65# This is positive but not a perfect square, so the roots of #f(x) = 0# and coefficients of the linear factors are real but irrational. #f(x)=0# has roots given by the ...