2018年3月18日 · x=6 >"isolate x by dividing both sides by 3" (cancel(3) x)/cancel(3)=18/3 rArrx=6" is the solution"

2016年6月18日 · 4 when seeing this type of question 0/0 you need to use L Hospital LAW lim_(x->-3)(2x^2-18)/(x+3) =lim_(x->-3)(4x)/x =4 '~~~~~ May I suggest the following solution ...Tony …

2018年3月3日 · color(red)(= (x^2+6)(x+3)) [Grouping the first 2 terms together and the 2md 2 terms together.] x^3+3x^2+6x+18 = (x^3+3x^2)+(6x+18) [Common factor] = x^2(x+3)+6(x+3 ...

2018年5月20日 · x+6 (x^2-3x-18)/(x+3) we need to factor first, the denominator will not factor but the numerator factors to: ((x + 3) (x - 6))/(x+3) now cancel the factor x+3 and we have the …

2016年6月27日 · The x-coordinate of the vertex is given by: #x=-b/(2a)# when #y=ax^2+bx+c#. Since a=3, b=-18 and c=3, you have. #x=-(-18)/(2*3)# #x=3# You can obtain the y-coordinate …

2015年8月8日 · By inspection you need 2 numbers that multiply together to -18 and sum to -3. These numbers are -6 and 3. Therefore we have: x^2-3x-18=(x-6

2018年6月12日 · Shown below y=(x^3-3x^2 + 8x+18 )/x y= x^3/x - (3x^2)/x + (8x)/x + 18/x y = x^2 -3x + 8 +18x^(-1) => d/dx((x^3-3x^2 + 8x+18 )/x) = d/dx (x^2 -3x + 8 +18x^(-1) ) Use ...

2015年8月6日 · First, solve f(x) = x^2 - 9x + 18 = 0. Roots have same sign. Factor pairs of (18) --> (2, 9)(3, 6). This sum is 9 = -b.

2016年8月24日 · 96 Let f(x) = 2x^3+4x^2-32x+18 The remainder when f(x) is divided by (x-a) is f(a). So when divide by (x+3) = (x-(-3)) the remainder is: f(-3) = 2(-27)+4(9)-32(-3)+18 ...

What is the direct variation equation if f(x) varies directly with x and f(x) = –18 when x = 3? Is #x/y = 1/2# a direct variation equation? Is the equation #y = -15x# a direct variation, if so what is …