2014年5月9日 · Think of how many times 2 needs to be multiplied in order to get eight. 2 x 2 = 4. 4 x 2 = 8 . Therefore, since 3 '2's were used, x = 3

2019年1月31日 · 2 inches wide to 8 inches wide is a scale (multiplication ) factor of 4 (because 2 x 4 = 8) so the 'tall-ness' has to multiply by this factor also..... 1.5 in x 4 = 6 inches tall

-2/1 x 4/3 = -8/3 (multiply the two numerators together -2 x 4 = -8 and multiply the two denominators together 1 x 3 = 3) As a mixed fraction, it is -2 2/3 geno3141 Oct 9, 2014

2014年8月15日 · 8(2)+2(2)=10(2) 16+4=20. 20 = 20 . This a true statement, so it works. Let's try it with one more number. 8x+2x = 10x. 8(9)+2(9) = 10(9) 72+18=90. 90=90 . Again, this is true, so we know we can do this next step I explained. ----- Let's do that step. -4 = 8x +2x -6 -4 = 10x - 6 ---Now add 6 to both sides. The will "erase" the 6 from the right side.

2019年6月18日 · 1. The graphs of y = x^3 - 3x + 2 and x + 4y = 4 intersect in the points , and . If and , compute the ordered pair (A,B). 2. Compute .

2019年1月15日 · (x + 2)(x - 4) expand . x^2 + 2x - 4x - 8 . x^2 - 2x - 8 . The x coordinate of the vertex is -(-2) / (2 * 1) = 2 /2 = 1. The y coordinate of the vertex is (1)^2 - 2(1) - 8 = 1 - 2 - 8 = -9. So...the vertex is (1, - 9) A second point can be found if we let x = 0 (0)^2 - 2(0) - 8 =-8. So (0, - …

2023年2月1日 · 3x + a = x^2 + x. 3x + a - x^2 - x = 0. x^2 + 2x + (3-a) = 0 . We can now use the quadratic formula to find the solutions for x: x = (-b ± √(b^2 - 4ac)) / 2a. x = (-2 ± √(2^2 - 4 * 1 * (3-a))) / 2 * 1. x = (-2 ± √(4 + 4a - 4 * 3)) / 2. x = (-2 ± √(4a - 8)) / 2 . Since the two points of intersection are distinct, the square root must ...

2020年12月10日 · a (x^4 - 8 x^3 + 8 x^2 + 52 x - 77) Since f(0) = -154 . Then . a (-77) = -154. a = -154/-77 = 2 . So....the polynomial is . 2 [ x^4 - 8 x^3 + 8 x^2 + 52 x - 77 ] = 2x^4 - 16x^3 + 16x^2 + 104x - 154 . And we just need to add all the coefficients plus the constant term to get f(1) = 2 - 16 + 16 + 104 - 154 = -48

2016年4月7日 · Find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) 8 sec^2 x + 4 tan^2 x − 12 = 0

2016年4月18日 · x^2 + 4x = 12 take 1/2 of 4 = 2.....square it = 4 and add to both sides . x^2 + 4x + 4 = 12 + 4 simplify the right, factor the left (x + 2)^2 = 16 take the pos/neg square roots of both sides . x + 2 = +/- square root (16) x + 2 = +/- 4 . We have two equations . x + 2 = 4 and x + 2 = -4 . Subtract 2 from both sides