5x^1.5 First, to check, I believe your expression is 25x^3. In that case we have 25=5^2 so sqrt25=5 And sqrt(x^3) = x^(3/2)=x^(1.5) Multiplying the two you get sqrt(25x^3) =5x^(3/2)=5x^(1.5)

2016年5月18日 · #sqrt(25x^3)# #color(white)("XXX")=sqrt(25)*sqrt(x^2)*sqrt(x)# #color(white)("XXX")=5*x*sqrt(x)#

2017年1月7日 · Then g(x) = x^3 and h(x) = sqrt(x + 25). We can differentiate g(x) using the power rule. g'(x) = 3x^2 We need the chain rule for h(x). Let y = sqrt(u) = u^(1/2) and u = x + 25.

2014年11月14日 · If you are looking for real solutions, then there are none. If you are looking for complex solutions, then (x-3)^2+25=0 by subtracting 25, => (x-3)^2=-25 by taking the square-root, =>x-3=pmsqrt{-25}=pm5i by adding 3, => x=3 pm 5i I hope that this was helpful.

2016年5月27日 · How do you find the limit of #(x^2 - 25) / (x^3 - 125)# as x approaches 5? Calculus Limits Determining Limits Algebraically. 1 Answer

2016年9月2日 · x^6+10x^3+25 = (x^3+5)^2 = (x+root(3)(5))^2(x^2-(root(3)(5))x+root(3)(25))^2 The sum of cubes identity can ...

2016年9月12日 · x = - 3, 7 We have: (x - 2)^(2) = 25 First, let's take the square root of both sides of the equation: => x ...

2016年4月13日 · =>x=8 or x=-2 Take the square root of both sides giving sqrt( (x-3)^2) = +-sqrt(25) Technically it should be +-sqrt( (x-3)^2) = +-sqrt(25) But the same answer would ...

2016年11月11日 · x^3+9x^2+15x-25 = (x-1)(x+5)^2 Given: x^3+9x^2+15x-25 First notice that the sum of the coefficients is 0. That is: 1+9+15-25 = 0 Hence x=1 is a zero and (x-1) a factor: x^3+9x^2+15x-25 = (x-1)(x^2+10x+25) To factor the remaining quadratic note that both x^2 and 25 = 5^2 are perfect squares, with 10x = 2(5)x. So this quadratic is a perfect square trinomial: …

2017年5月19日 · How do you use synthetic division to evaluate #f(3)# given that #f(x)=x^3+2x^2-7x+8#? See all questions in Synthetic Division Impact of this question