2018年7月18日 · #((x+5)(x-5))/(x-5)# Common factors cancel, and we're left with. #lim_(xto5) x+5=5+5=color(blue)(10)# Calculus Way: We can use L'Hôpital's rule, which says if we want to …

2016年2月19日 · To solve means to isolate. x + 5y = 25 5y = 25 - x y = 25/5 - x/5 y = 5 - x/5 or (25 - x)/5. How do you determine the amount of liquid a paper cone can hold with a 1.5-inch …

symbol. A * symbol is not necessary when multiplying a number by a variable. For instance: 2 * x can also be entered as 2x. Similarly, 2 * (x + 5) can also be entered as 2(x + 5); 2x * (5) can be …

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2016年11月1日 · We start by factoring both the numerator and the denominator. =lim_(x->5)((x + 5)(x- 5))/((x - 5)(x + 1)) =lim_(x -> 5) (x + 5)/(x + 1) =(5 + 5)/(5 + 1) =10/6 =5/3 ...

2016年8月15日 · lim_(x ->-5)(x^2 - 25)/(x + 5) = -10 Start by eliminating through factorization: =lim_(x -> -5)(cancel((x + 5))(x - 5))/cancel(x + 5) = -5 - 5 =-10 Hopefully this helps!

2016年11月29日 · 10 lim_(x->5) (x^2-25)/(x-5) = lim_(x->5) ((x-5)(x+5))/(x-5)= lim_(x->5) (x+5) = 10. Is there a number "a" such that the equation below exists?

2015年5月30日 · First thing we should know is; 25^b=(5^2)^b=5^(2b) This is a basic rule to be memorised. So our question is; 5^x=25^(x-1) We can write it as ; 5^x=(5^2)^(x-1) => 5^x= …

2018年4月22日 · Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one …

2015年9月13日 · (x^2-25)/(x-5) = x+5 with exclusion x != 5 Use the difference of squares identity: a^2-b^2 = (a-b)(a+b) to find: (x^2-25)/(x-5) = (x^2-5^2)/(x-5) = ((x-5)(x+5))/(x-5 ...