
Prove that CotA/2-3cot3A/2=4sinA/1+2cosA? - Socratic
2018年2月11日 · What are the units used for the ideal gas law?
How do you verify #2cos(a+b)sin(a-b) = sin(2a) - sin(2b)#? - Socratic
2016年7月9日 · How do you use the sum and difference identities to find the exact value of tan 105 degrees
#(CosA+2CosC)/(CosA+2CosB)= SinB/SinC#, Prove that the
2018年3月4日 · Given #rarr(cosA+2cosC)/(cosA+2cosB)=sinB/sinC#. #rarrcosAsinB+2sinB*cosB=cosAsinC+2sinCcosC# #rarrcosAsinB+sin2B=cosAsinC+sin2C#
How do you prove #2 cos^2 A - 1 = cos(2A)#? - Socratic
2016年3月14日 · How do you find all solutions for #sin 2x = cos x# for the interval #[0,2pi]#?
How do we write cos3A in terms of cosA? - Socratic
2017年6月14日 · #cos3A=cos(A+2A)# = #cosAcos2A-sinAsin2A# = #cosA(2cos^2A-1)-sinA(2sinAcosA)# = #2cos^3A-cosA-2sin^2AcosA# = #2cos^3A-cosA-2(1-cos^2A)cosA#
Prove that #cot(A/2)-3cot((3A)/2)=(4sinA)/(1+2cosA)#? - Socratic
2018年5月24日 · #LHS=cot(A/2)-3cot((3A)/2)# #=cos(A/2)/sin(A/2)-(3cos((3A)/2))/sin((3A)/2)# #=(cos(A/2)sin((3A)/2)-3cos((3A)/2)sin(A/2))/(sin(A/2)sin((3A)/2))#
The formula for cos3A? - Socratic
2018年3月14日 · Use the cosine angle addition formula, then the sine and cosine double angle formulas: #color(white)=cos3A# ...
How do you simplify #tanA - cscA secA (1 - 2cos^2 A)#? - Socratic
2015年11月13日 · If we multiply the top and bottom of the tangent term by sinA, we get a denominator of sin A cos A. sin^2 A / (sin A cos A) - 1/(sin A cos A)+(2cos^2A) /(sin A cos A) Combine the numerators. (sin^2A -1 + 2cos^2A)/(sinAcosA) Now we split the 2cosA term into cosA + cosA. I rearranged a little to make the next step more aparent.
Prove that #cot (A/2)- 3cot ((3A)/2) = (4sinA)/(1+2cosA)#? - Socratic
2018年2月20日 · #LHS=cot(x/2)-3cot((3x)/2)# #=cos(x/2)/sin(x/2)-3*cos((3x)/2)/sin((3x)/2)# #=(sin((3x)/2)*cos(x/2)-3*cos((3x)/2)*sin(x/2))/(sin(x/2)*sin((3x)/2)#
Prove that? sqrt (2+sqrt (2+sqrt (2+2cos8theta = 2costheta
2017年9月19日 · sqrt(2+sqrt(2+sqrt(2+2cos8theta)))=2costheta As cos2A=2cos^2A-1, we have cos8theta=2cos^2(4theta)-1, cos4theta=2cos^2(2theta)-1 and cos2theta=2cos^2theta-1 i.e. 1 ...