2017年2月8日 · ((2n-1)!)/((2n+1)!) = 1/((2n+1)(2n)) Remember that: n! =n(n-1)(n-2)...1 And so (2n+1)! =(2n+1)(2n)(2n-1)(2n-2) ... 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \=(2n+1)(2n)(2n-1)!

2016年10月18日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …

2018年8月1日 · $2n\ -\ 1$ is clearly odd because $(2n\ -\ 1)\ \text{mod}\ 2\ =\ 1$. So $2n\ -\ 1$ is an arbitrary odd number by definition. But adding 2 results in $2n\ +\ 1$ which is odd for the …

I'm a little confused as to how $(2n)!/(2n+2)!$ looks when written out. Basically I'm trying to visualise it so that I know how to cancel this and like terms in future.

2015年1月27日 · Your expression for $(2n)!$ is correct. You can't easily split it down. You might want to use $$\binom {2n}{n}=\frac {(2n)!}{n!n!}=\frac {n+1}{n}\frac{(2n)!}{(n+1)!(n ...

2015年10月15日 · sum_{n=1}^infty 1/{2n+1} = infty By comparison, you can say that 2n+1 ~~ n. They are asymptotically equivalent because lim_{n \to \infty} (2n+1)/n = 2. So, the series …

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2015年11月24日 · 33097 views around the world You can reuse this answer ...

2019年11月2日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …

Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …