
Factor 2x^2-3x+1 - Mathway
Factor the polynomial by factoring out the greatest common factor, 2x−1 2 x - 1. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.
Equation Solver - Mathway
The equation solver allows you to enter your problem and solve the equation to see the result. Solve in one variable or many.
解方程2x^2-3x+1=0怎么算_作业帮 - zuoyebang
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Algebra Calculator - Symbolab
Begin by typing your algebraic expression into the above input field, or scanning the problem with your camera. After entering the equation, click the 'Go' button to generate instant solutions. The calculator provides detailed step-by-step solutions, aiding …
Graph f(x)=2x^2-3x+1 | Mathway
Graph the parabola using its properties and the selected points. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.
方程计算器 - Symbolab 数学求解器
免费的方程计算器 - 一步步求解线性方程,二次方程,多项式方程,根式方程,指数方程,对数方程。 输入方程即可获得解,步骤和相应图形.
solve by factoring 2x^2-3x+1 - Symbolab
x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)
Solve 2x^2-3x+1 | Microsoft Math Solver
Rewrite 2x^ {2}-3x+1 as \left (2x^ {2}-2x\right)+\left (-x+1\right). Factor out 2x in the first and -1 in the second group. Factor out common term x-1 by using distributive property. If a line parallel to y=-7x+3 touches the parabola 2x^2-3x+2 in the point (x_0,y_0), what is the value of 4x_0+y_0?
求解 2x^2-3x-1 | Microsoft Math Solver
可使用变换式 ax^ {2}+bx+c=a\left (x-x_ {1}\right)\left (x-x_ {2}\right) 对二次多项式进行因式分解,其中 x_ {1} 和 x_ {2} 是二次方程式 ax^ {2}+bx+c=0 的解。 形式为 ax^ {2}+bx+c=0 的所有方程式均可求解,方法是使用二次公式来求解: \frac {-b±\sqrt {b^ {2}-4ac}} {2a}。 此二次公式可得到两个解,一个是当 ± 取加号时的解,另一个是取减号时的解。 现在 ± 为加号时求公式 x=\frac {3±\sqrt {17}} {4} 的解。 将 \sqrt {17} 加上 3。 现在 ± 为减号时求公式 x=\frac {3±\sqrt {17}} {4} 的解。
在线方程式计算器 - OK Calculator
令 $x^2$ 为 $y \ (y \ge 0)$,就变成了一个二次方程式,可以求出它的两个根 $y_1, y_2$。 二次次方程式的根可通过如下方式求出: $$x_{1,2} = \pm \sqrt {y_1}, \ \ \ x_{3,4} = \pm \sqrt {y_2}$$