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2 (x+3)=10 One solution was found : x = 2 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ... How do you solve 2x+3 =11 ? \displaystyle {\left ( {x}= {4}\right.}

x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)

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What is the answer to 2(x-3)=10 ? The answer to 2(x-3)=10 is x=8; Solve for x: 2(x-3)=10; The solution is x=8

2(x +3) = 10. Here 2 is multiplied with both the terms within the bracket. 2 × (x) +2 ×(3) = 10. 2x +6 = 10. 2x = 10− 6. 2x = 4. x = 4 2. x = 2. color (green) (x=2 color (blue) (2 ) (x+3) = 10.

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