Solve the Equation 2x-3=7 - Answer | Math Problem Solver - Cymath ... \\"Get

2017年1月18日 · x = 10 or x = -2 We know that if absa = b, a = +-b. First, remove the absolute value. Since we do not know if 2x - 3 is positive or negative, we will need a +- on the 7: abs(2x - 3) = 7 => 2x-3 = +- 7 Then, add 3 to both sides, and finally divide by 2: 2x = 3 +- 7 x = 3/2 +- 7/2 So x is equal to either 10/2 = 5 or -4/2 = -2.

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2015年12月4日 · Here, the solution is -3/2 <= x <= 2 or x in [-3/2; 2] 2) x < -3/2: -(2x + 3) <= 7 <=> -2x - 3 <= 7 <=> -2x <= 10 ... divide by -2 and don't forget to flip the inequality sign (this needs to be done if multiplying with or dividing by a negative number)... <=> x >= -5 Don't forget to take a look at the condition x < -3/2 which needs to hold at ...

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2018年3月10日 · x~~546.817 or x=(e^7 -3)/2 Remember, anytime you see ln, it is always equal to loge (the e is a subscript). You work with them the same way as you would any other log. Problem: ln(2x+3)=7 Step 1: take loge of both sides. ln(2x+3)=ln(e^7) Step 2: Since the logs have the same bases, make the (2x+3)=(e^7) equal to each other Step 3: Solve so the x is on the …

2018年1月12日 · #color(red)(3-2x >7# Subtract the value of 3 from both sides #3-2x - 3 >7 - 3# #rArr cancel 3-2x - cancel3 >7 - 3# #rArr -2x > 4# Multiply both the sides by #(-1)# We must remember to reverse the inequality. #rArr -2x (-1) < 4 (-1)# #rArr 2x < -4# Divide both sides by the value of 2. #rArr (2x)/2 < -4/2# #rArr (cancel 2x)/cancel 2 < -4/2#

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