How do you solve for y in #x-2y=2#? - Socratic
2016年5月28日 · y=x/2-1 color (brown) ("When you see a question of this type ")your objective is to end up with something like y="'something'". You do this in stages. First isolating all the terms that contain your target variable on one side of the equals and everything else on the other side.
How do you factor x^2 - y^2 ? + Example - Socratic
2015年7月7日 · This is known as a difference of squares. It can be factored as: x^2 - y^2 = (x-y) (x+y) Notice that when you multiply (x-y) by (x+y) then the terms in xy cancel out, leaving x^2-y^2 ... (x-y) (x+y) = x^2+xy-yx-y^2 = x^2+xy-xy-y^2 = x^2-y^2 In general, if you spot something in the form a^2-b^2 then it can be factored as (a-b) (a+b) For example: 9x^2-16y^2 = (3x)^2- …
How do you factor xy-2y-x+2? | Socratic
2018年4月16日 · factor the terms by grouping ⇒ y(x −2)−1(x − 2) take out the common factor (x −2) = (x −2)(y − 1) ⇒ xy − 2y −x +2 = (x − 2)(y − 1)
How can I solve this differential equation? x dy/dx+y=x^2y^2
2018年2月18日 · This equation is a Bernoulli equation as it can be rewritten to the form dy dx + f (x)y = g(x)yn. From x dy dx + y = x2y2, one can divide both sides by x so that it fits the Bernoulli form.
How do you differentiate e^ (x^ (2)y) = 2x + 2y? | Socratic
2015年5月24日 · Take one side at a time. Let f (x, y) = e^ (x^2y). [ (df)/ (dx)]_"left" = (e^ (x^2y)) [x^2 (dy)/ (dx)+y*2x] (chain rule, product rule) [ (df)/ (dx)]_"right" = 2 + 2 ...
How do you find ( (d^2)y)/ (dx^2)? - Socratic
2016年11月3日 · Defining f (x,y(x)) = 2xy(x) + 2y(x)2 − 13 = 0 then df dx = 2y +2xy' +4yy' = 0 and d dx df dx = 4y' +2xy'' + 4y'2 +4yy'' = 0 after substitution of y' we have y'' = 2xy + 2y2 (x + 2y)3 = 13 (x +2y)3 but y = 1 2 (−x ± √26 + x2) so finally y'' = ± 13 (26+ x2)3 2
Implicit Differentiation - Calculus | Socratic
Implicit differentiation allows differentiating complex functions without first rewriting in terms of a single variable. For example, instead of first solving for y=f(x), implicit differentiation allows differentiating g(x,y)=h(x,y) directly using the chain rule.
How do you factor x^2-xy-2y^2? | Socratic
2016年7月29日 · x2 −xy − 2y2 = x2 −2xy +xy − 2y2 = x(x −2y) +y(x − 2y) = (x +y)(x − 2y)
How do you find the slope of the following line, x+2y= -2
2015年4月1日 · I would rearrange the equation to actually "see" the slope, as: 2y=-x-2 y=-x/2-2/2 y=-1/2x-1 The slope is the numerical coefficient in front of your x, i.e., -1/2
How do you graph using the intercepts for - 2y = -2? | Socratic
2015年11月9日 · The x and y intercepts give us two points on the line defined by the linear equation. The x-intercept is the value of x when y = 0 (for all points on the X-axis y = 0) Given 5x + 2y = − 2 when y = 0 ⇒ XXXx = − 2 5 which gives the point (− 2 5,0) Similarly for the y-intercept we get the point (0, −1)