2016年3月13日 · How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#?

2015年4月8日 · x^2 - 3x = 0 x*(x-3) = 0 (x was a common factor to both the terms) In general, if a*b = 0, then either a ...

2025年2月27日 · 7 – 4 + 3 x 0 + 1 = ? The author is challenging what the average person knows. The correct answer is, of course, 4. So many people out there insist that it's 1. After all, …

2017年4月24日 · See below. For my approach, I will be using a graphical interpretation. You can rewrite the equation as x^3 - x - 1 = 0 as the first step. Then graph the following: f(x) = x^3 - x - …

2016年11月30日 · How do you solve #x^3-1=0#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers. 1 ...

2018年1月30日 · After trial and error, we see that #(2,0)# is the #x#-intercept. We now divide #x^3+x-10# by #x-2# to get #x^2+2x+5# We now try to find the #x# intercept of #x^2+2x+5# .

2018年6月3日 · The roots are -1,-1,2 It is easy to see by inspection that x = -1 satisfies the equation : (-1)^3-3times(-1)-2 = -1+3-2=0 To find the other roots let us rewrite x^3-3x-2 …

2016年9月13日 · pi/2, (3pi)/2 for (0, 2pi) Property of complementary arcs--> sin (pi/3 + x) = cos (pi/2 - (pi/3 + x)) = cos (pi/6 - x) Use trig identity: cos a + cos b = 2 cos ((a ...

2018年3月21日 · The only solutions on the given interval are x=0, quad pi/2, quad pi, quad (3pi)/2. You can use a substitution, then solve it like a regular polynomial.

2016年12月15日 · There are probably more elegant solutions, but here are two. Let f(x) = (1+x^3)^(1/2) and note that f(0) = 1. Furthermore, f'(x) = (3x^2)/(2sqrt(1+x^3)) which is always …