x=0 4^x-2^x=0 4^x=2^x Apply the natural logarithm to both sides: ln(4^x)=ln(2^x) Recalling that ln(a^b)=bln(a): xln(4)=xln(2) So, x=0 is obviously a solution as it will result in 0=0. Beyond that, there are no solutions as x cancels out and we're left with ln(4)=ln(2) which is not true.

2016年11月2日 · x= 0, -4 x(x+4) = 0 x/x(x+4) = 0/x x+4 = 0 x+4-4 = 0-4 **x = -4** x(x+4) = 0 x((x+4)/(x+4)) = (0/(x+4 )) **x = 0**

2015年8月24日 · d/dx(4^x) = 4^x ln4 In general for b>0, we have d/dx(b^x) = b^x lnb And when we need the chain rule, we have d/dx(b^u) = b^u (lnb) d/dx(u) Proof of General rule b^x = (e^lnb)^x " " (remember that e^lnu = u) So b^x = e^(xlnb) " " (because (a^r)^s = a^(rs) = a^(sr)) d/dx(e^(xlnb)) can be found by the chain rule: d/dx(e^(xlnb)) = e^(xlnb) d/dx(xlnb) = e^(xlnb) lnb " " (lnb is a constant) = b^x ...

2019年5月3日 · Find the mean and standard deviation for the random variable x given the following distribution Answers · 3 using interval notation to show intervals of increasing and decreasing and postive and negative

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2018年4月11日 · x=0 or x=5/4 The quadratic formula for ax^2+bx+c=0 is given by x=(-b+-sqrt(b^2-4ac))/(2a) a=4, b=-5, c=0 therefore x=(-(-5)+-sqrt((-5)^2-4(4)(0)))/(2(4)) x=(5+-sqrt ...

2016年7月31日 · One of the properties of zero is that "Anything times 0 is equal to 0" So, # a = 0, or b=0, or c=0, or d=0.# To have a 0 from multiplying means we must start with a 0. In #(x-4)(x-3)=0" "# we have the product of two factors equal to 0, ONE of them MUST be 0. If #x-4 = 0" "rArr x = 4# If #x-3 = 0" "rArr x = 3# These are the two solutions.

2018年3月5日 · What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72?

2016年4月2日 · If you need to find all values of x between 0 and 360 (or 0 to 2pi), there would be 8 answers. If x goes from 0 to 360, then 4x goes from 0 to 1440. For example, 90, 450, 810, and 1170 are all coterminal (just adding 360 each time), but if we set them equal to 4x, then you get 4 angles that make your equation work.

2015年8月3日 · x=0,4 Factor the expression: x^2-4x=x(x-4)=0 Therefore x=0 and x=4 are the solutions.