2016年7月27日 · To solve the quadratic equation 40 − x 2 = 0, we first rearrange it to the standard form of a quadratic equation, which is a x 2 + b x + c = 0. In this case, we can rewrite it as x 2 …

x − 2 = 3 − 40 x = 2 + 3 − 40 x ≈ 2 − 3.42 ≈ − 1.42 Step 3: Find the intercepts Now, we check where the original graph intersects the x-axis. Setting f ( x ) = 0 gives us the same equation, …

2018年3月5日 · To convert the quadratic function f (x) = x 2 + 14 x + 40 into vertex form, we need to complete the square. The vertex form of a quadratic function is given by f (x) = a (x − h) 2 + …

2024年12月10日 · x = 0: Generally, having a dimension of zero would result in a volume of zero, which wouldn’t match the given 40 cubic meters, so this option is less likely to be correct. …

2019年10月8日 · For example, if we choose x = 2 10 , we can substitute back into the original equation to verify: 40 − (2 10 ) 2 = 40 − 40 = 0, confirming that our solution is correct. Similarly, …

To find the quotient and remainder using partial fractions, we first perform polynomial long division to divide 2x^3 - 25x + 40\) by \(x^2 + 2x - 8\ The division looks like this: 2 x + 6. x 2 + 2 x − 8∣2 …

2017年7月31日 · The polynomial 12 x 4 + 17 x 3 + 8 x − 40 divided by x + 2 yields a quotient of 12 x 3 − 7 x 2 + 14 x − 20 with a remainder of 0. This means the division is exact with no …

The correct representation of the** re-grouping f**or 45 x 12 is: 40 x 10; 5 x 10; 40 x 2; 5 x 2. This method is a way of breaking the** multiplication **down to enable easier calculation: 40 x 10 is …

2018年6月22日 · For example, if we substitute x = 2 10 back into the original equation, we should verify that it equals zero: 40 − (2 10 ) 2 = 40 − 40 = 0 This proves that 2 10 is indeed a …

2017年7月13日 · − 40 1 x 2 = y. we can start by rewriting it in a standard form. Rearranging the equation, we have: y = − 40 1 x 2. This shows us that the parabola opens downwards since …