SOLUTION: if {x^2-3x-40} divided by {x+5} x^2-3x-40 divided by x+5 x^2-5x -2x-40 -2x- 10 =30 x-2+30 x-30 I keep trying the problem to see were i made my mis

You can put this solution on YOUR website! 5/200=x/40 200x=200 x=1

Algebra -> Proportions-> SOLUTION: 5:200 as X:40 X= Log On Algebra: Proportions Section. Solvers ...

2024年5月28日 · Given that the speed of light is approximately 3.00 x 10^10 cm/s, the frequency of radiation with a wavelength of 2.40 x 10^-5 cm would be approximately 1.25 x 10^15 Hz. This answer is:

Question 883062: A 40 inch board is to be cut into 3 pieces so that the second piece is twice as long as the first piece, and the third piece is 5 times as long as the first piece. If x represents the length of the first piece, find the lengths of all three pieces. So I did: 40= x+2x+5x - 40=8x - (40/8=5) x=5? I don't know if that is correct.

Algebra -> Probability-and-statistics-> SOLUTION: X is a normal variate with mean 30 and standard deviation 5. Find the probabilities that 1. 26< X <40 2. x>45 Log On Algebra: Probability and statistics Section

let x = the amount invested in bonds. let y the amount invested in mutual funds. everything will be converted to millions for ease of presentation. your constraint functions are: x + y = 40 x >= 5 y >= 20 .0001 * x + .0002 * y = .007 x >= 0 y >= 0 your objective function is .03 * x + .05 * y this is what you want to maximize.

To represent that gap more generally, we write 40-x where 0 x 40 is the case. Then multiply that with the $25 mentioned to get 25(40-x). You could distribute the 25 through, but I advise against it. Why? Because you lose the info about the gap from 40 to …

The gap between adjacent tickmarks is a gap of 1 standard deviation, which in this case is 5 units. In other words, the gap between any adjacent tickmarks is 5 units. If we started at the center (mean = 30) and moved 1 tickmark or standard deviation to the right, then we arrive at 30+5 = 35. Another tickmark over and we arrive at 30+2*5 = 40 ...

f(x)=7x^4 +27x^3 -40x^2 +x +5 Algebra -> Rational-functions -> SOLUTION: The function below has at least one rational zero. Use this fact to find all zeros of the function.