If you can choose to use less of the items in a sequence that changes things. 1 item used = 6 possibilities . 2 items used is 5 possibilities for each item because there are only 5 left to …

2018年9月5日 · So i have 6 different flavours. I intend to mix these flavours together where the total amount would be 100 % when all the 6 different flavours has been counted. This means …

Well, there are $\binom{6}{2}$ ways to pick the first pair of objects, $\binom{4}{2}$ ways to pick the second pair of objects, and $\binom{2}{2}$ ways to pick the third pair of objects. But since …

Unique combinations (order does matter; items repeat) combinations with 1 item 4 combinations with 2 items 4^2 = 4*4 = 16 combinations with 3 items 4^3 = 4*4*4 = 64 combinations with 4 …

2021年1月22日 · The answer is no. Let us number the items from 1 to 6. How many ways you can draw 4 items from a box containing 6 different but indistinguishable items (and put it back after …

2021年2月25日 · Given inventory quantity, how many sellable items will I have given an item is sold on a buy 4 get 1 free basis 20 If two pairs of numbers have equal sums and products, …

There are $6!$ distinct ways to place $6$ items into six slots. Consider the first two slots as the first pair, the second two slots as the second pair, and the last two slots as the last pair. Within …

2019年3月28日 · Im trying to figure out how to place a number of items into containers evenly but without splitting. Easy example: 11 items, 2 containers. 11/2 = 5.5. so even distribution would …

2018年6月3日 · In the 4-set example (wxyz), there are 6 unique combinations. But where n is 4, your formula would give (2^4) - 4 - 1 = 16 - 4 - 1 = 11, which is more than 6. Have I made a …

2020年4月26日 · You have won first place in a contest and are allowed to choose 2 prizes from a table that has 6 prizes numbered 1 through 6: Prizes 1&2 are mobile phones, Prizes 3&4 are …