2020年4月18日 · Prove that sin ( -690^°) cos (-300^°) + cos (-750^°) sin (-240^°) = 1 - 16705109

2018年6月24日 · Click here 👆 to get an answer to your question ️ Evaluate sin(-690°)cos(-300°)+cos(-750°)sin(-240°) axdtyjerrinas9839 axdtyjerrinas9839 24.06.2018

2023年9月22日 · Therefore, the assertion (A) that the value of sin(–690°)cos(–300°) cos(–750°)sin(–240°) = 1 is not true. Conclusion: The reason (R) that the values of sin and cos are negative in the third and fourth quadrants respectively does not support the assertion (A), as the value of the expression is -0.1885, not 1.

2023年9月22日 · The assertion claims that the product of the sine and cosine values of these angles results in 1, implying that sin(–690°)cos(–300°) cos(–750°)sin(–240°) = 1. 2. The reason provided is that the values of sin and cos are negative in …

2024年6月8日 · Assertion (A): The value of sin(-690°) cos(-300)cos(-50° sin(- 240 ) = 1. Reason (R): The values of sin and cos is negative in third and fourth quadrant respectively. a) Both A and R are true and R is the correct explanation of A. b) Both A and R are true but R is not the correct explanation of A. c) A is true but R is false.

2018年6月30日 · Find an answer to your question sin (-690)×cos (-300) + cos (-750)× sin (-240)=1 prove that priyanka32oyp priyanka32oyp 01.07.2018

2019年7月17日 · SI TUUUUTUUGi) sin 690° cos 930° + tan (-765º) cosec (- 1170°). π2Tπ Get the answers you need, now! Harshitakrit Harshitakrit 17.07.2019

2020年10月6日 · Click here 👆 to get an answer to your question ️ (ii) sin 690° cos 930° + tan (-765°) cosec (-1170°) roshnimishra09 roshnimishra09 07.10.2020

2020年11月19日 · Click here 👆 to get an answer to your question ️ sin 480° cos 690° + cos 780° sin 1050° mujeebtetra mujeebtetra 20.11.2020

2023年1月4日 · Click here 👆 to get an answer to your question ️ sin(-690)cos(-330)+cos(-750)sin(-240) 918329079354 918329079354 04.01.2023