2017年4月14日 · The general vertex form is #color(white)("XXX")f(x)=color(green)m(x-color(red)a)^2+color(blue)b# with vertex at #(color(red)a,color(blue)b)#

2017年6月16日 · Axis of symmetry is x=1, vertex is at (1,15). f(x)= -3x^2+6x+12= -3(x^2-2x)+12 = -3(x^2-2x+1)+3+12 = -3(x-1)^2+15 . Comparing with standard vertex form of equation f(x)= a(x …

2018年6月14日 · expand brackets 7x-12x+24\leq6x+12-9x Collect like terms 24-5x\leq12-3x add 5x 24\leq12+2x subtract 12 12\leq2x divide by 2 6\leqx

2017年12月31日 · #"take out "color(blue)"common factor of 2"# #rArr2(x^3+2x^2+3x+6)# #"when "x=-2tox^3+2x^2+3x+6=0# #rArr(x+2)" is a factor"#

2018年6月12日 · We have the inequality #color(red)(6x+4y>12#. Subtract #color(blue)(6x# from both sides of the inequality #6x+4y-color(blue)(6x)> 12 - color(blue)(6x#

2015年7月18日 · Slope is indeterminate and never crosses the y axes. Your equation represents a vertical line that you can write as: x=12/6 or: x=2 The slope of this line is indeterminate and it …

2017年3月21日 · How do you solve #4x^2+6x=12# by completing the square? Algebra Quadratic Equations and Functions Completing the Square. 1 Answer

2018年3月20日 · Given: #0=x^2-6x+12# #color(brown)("The question specifically equates to 0. So we must find a solution that")# #color(brown)("works for "y=0.

2015年3月30日 · First divide both sides of the equation by the coefficient of x^2 (in this case 3) x^2+2x+4=0 If x^2 + 2x are the first 2 terms of an expression from (x+a)^2 then a=1 Rewrite …

2016年11月1日 · The zeros of f(x) are: x = +-sqrt(6)" " (irrational) x = 2" " (rational) The difference of squares identity can be written: a^2-b^2 = (a-b)(a+b) We use this with a=x and b=sqrt(6) …