2013年7月8日 · The total (a) minus what was shared equals the remainder of the division Applied to the last example, this gives: 5 % 7 = 5 - floor(5 / 7) * 7 = 5 Modular Arithmetic That said, …

2009年8月30日 · I'm embarrassed to ask such a simple question. My term does not start for two more weeks so I can't ask a professor, and the suspense would kill me. Why does 2 mod 4 = 2?

How does mod of power of 2 work on only lower order bits of a binary number (1011000111011010)? What is this number mod 2 to power 0, 2 to power 4? What does …

2015年11月17日 · Careful with the terms mod and modular because n (mod m) IS ALWAYS >= 0 but not n % m. n % m is in the range > -m and < m. Although Java has a remainder operator …

2010年5月9日 · 9 = 2^X mod 11 What is X and how do you find X? Its related to finding the plain text in RSA algorithm and I'm writing a C program for it.

2012年6月4日 · I have configured my Apache by myself and have tried to load phpMyAdmin on a virtual host, but I received: 403 Forbidden You don't have permission to access / on this server …

2024年10月2日 · You can think of the modulus operator as giving you a remainder. count % 6 divides 6 out of count as many times as it can and gives you a remainder from 0 to 5 (These …

2010年2月1日 · How to calculate modulus of 5^55 modulus 221 without much use of calculator? I guess there are some simple principles in number theory in cryptography to calculate such …

2013年4月21日 · x % 2 gives the remainder after the integer division (when dealing with only integers such as in this case, otherwise a common type) of x/2. The % is called the modulo …

2012年12月12日 · I need to work out a very large power modulo (2^32), i.e. I want the result of: y = (p^n) mod (2^32) p is a prime number n is a large integer Is there a trick to doing this …