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1. x86-64寄存器和栈帧 - 知乎
在函数sfact_helper中,用到了寄存器%rbx和%rbp,在覆盖之前,GCC选择了先保存他们的值。 在函数返回之前,GCC依次恢复了他们。
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深入浅出GNU X86-64 汇编 - lsgxeva - 博客园
2019年7月12日 · 一般栈是从高地址到低地址向下生长的。 %rsp是栈指针,指向栈最底部 (其实是平常所说的栈顶)元素。 所以,push %rax(8字节),会把%rsp减去8,并把%rax写到 %rsp指向的位置。 SUBQ $8, %rsp MOVQ %rax, (%rsp) pop则刚好相 …
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如何计算*0x402470 (,%rax,8) - CSDN博客
2022年7月20日 · 先用p $rax 找出rax对应的值。 阔以看出rax存的数是5,接着我们来看 0x402470 (,%rax,8)。 这个其实等于0x402470 + 8 * rax = 0x402498,又因为前面有个指针,所以我们还要去 0x402498这个地址中寻找我们要的值,
X86-64系统的汇编指令_x86-64基础指令集-CSDN博客
将8个字节(Quad word)的数据从一个位置复制到另一个位置。 操作的是四字数据,但是立即数作为源操作数时只能表示32位。 将一个绝对的64位立即数移动到寄存器中。 只能以寄存器作为目的地,可以操作任意64位立即数。 pushq %rax,表示将%rax中值保存到栈中。 等效于. popq %rax,弹出栈顶元素,放入%rax中。 等效于: 不是将7+%rdx+%rdx*4这个地址中的值放入%rax。 逻辑右移。 用于无符号数. 几个例子: int b = -1; int t = a + b;//>>>发生zf 出现0. …
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