Determine all possible Jordan forms of the 2\times 2 matrices satisfying in p (x)=x^3-6x^2+11x-6

Multiply \frac {9} {5} times \frac {23} {18} by multiplying numerator times numerator and denominator times denominator.

23.5×24.5 = 575.75 Explanation: One way is to note that: 23.5×24.5 = (24 − 21)(24+ 21) =242 −(21)2 = 576− 41 =575.75

You can just look for a pattern. Each time you add 29 to a number, the remainder when divided by 23 increases by 6, so you can see that: 1≡1\pmod {23}, \;30≡7\pmod {23}, \;59≡13\pmod {23},\;\;...\;\;291≡15\pmod {23} ...

You can simply rewrite it as: ab+a+b=10a+b ab=9a One can see now, that b=9 and a can be anynumber such that 0 \leq a \leq 9.

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