2018年4月20日 · Aluminium reacts with sulfuric acid (h2so4) to produce aluminium sulfate al2(so4)3 and hydrogen (h2). Complete the balance the equation for this reaction?

2015年11月5日 · 2Al + 3H2SO4 = Al2(SO4)3 + 3H2 When balancing chemical equations I always start with oxygen and identify which compound has the most, which in our case is Al2(SO4)3. So because we have 4 O in SO4, and there are 3 of moles of SO4, so we multiple 4x3=12. So now, go to the opposite compound with O (H2SO4) and manipulate it to even out the O, in this case multiple by 3. Now we have 12 O on each ...

2017年9月18日 · How do I balance this equation? Al2O3+H2SO4=Al2(SO4)3+H2O. Chemistry. 1 Answer

2017年5月7日 · What mass of solid aluminium is needed to react with excess H2SO4(aq) to produced 20.0 L of H2(g) at 1.0 atm and 298 K?

2018年1月4日 · With reference to the given balanced equation for the mole ratios, the needed number of moles for each remaining compound involved in the reaction using the mass of #Al# as basis for the molar conversions can be computed as;

Mass is conserved rather than created or destroyed so when a chemical equation is written, it must be balanced so that there is the same amount of reactants going in as yielded product. The equation is balanced by changing the scalar numbers that precede each part of the equation.

Balancing a redox reaction requires identifying the oxidation numbers in the net ionic equation, breaking the equation into half reactions, adding the electrons, balancing the charges with the addition of hydrogen or hydroxide ions, and then completing the equation.

2018年4月18日 · Well, the balanced equation is...Zn(s) + H_2SO_4(aq) rarr ZnSO_4(aq) + H_2(g) As written, this is a redox reaction: zinc metal is oxidized; hydrogen ion is REDUCED.

2017年7月9日 · 80 "g Al(OH)"_3 (one sig fig) I'll assume you mean what mass of aluminum hydroxide reacted. We can use the coefficients of the equation to determine the number of moles of "Al(OH)"_3 that react, knowing that 1 "mol AlCl"_3 forms: 1cancel("mol AlCl"_3)((1color(white)(l)"mol Al(OH)"_3)/(1cancel("mol AlCl"_3))) = 1 "mol Al(OH)"_3 which makes sense given their molar ratio is 1:1. Now, we can use ...

2015年2月17日 · In order for you to actually calculate the molar mass of alum, a mass produced by the reaction should have been given to you. Since molar mass is defined as the mass of 1 mole of a substance, you'd need both the number of moles of alum - which you can easily calculate - and the mass produced - which you do not have. There are actually four reactions that take place here (I won't go into the ...