You can put this solution on YOUR website! Assume three events A.B.C are such that p(A)=0.5, p(B)=0.6, p(C)=0.4,p(AnB)=0.3,

You can put this solution on YOUR website! What is the probability of (AnBnC) if P(A) =.95; P(B) =.81; P(C) =.77

List the elements for (AnBnC) There is a FATAL ERROR in this post. The number 915 can not be in the set B, since the number 915 is not an element of the universal set S.

Question 1117933: Question 921226: From a city 3 newspapers A, B, C are being published. ‘A’ is read by 20%, ‘B’ is read by 16%, and

Question 394621: 5.Three computer viruses arrive as an email attachment. Virus A damages the system with probability 0.4.

You can put this solution on YOUR website! We use the fact that X - Y = X ∩ Y', where Y' = set complement of Y.

You can put this solution on YOUR website! Actually, the standard way to solve such problem is in one line as it is shown below: The number of those who own at least one of these devices = 70 + 120 - 41 = 149.

Question 1034027: A, B, C are three mutually independent with probabilities 0.3, 0.2 and 0.4 respectively. What is P (A B C)?

List the elements for (AnBnC) There is a FATAL ERROR in this post. The number 915 can not be in the set B, since the number 915 is not an element of the universal set S.