2018年3月15日 · This is not a rational number of degrees, nor a rational multiple of pi radians. We can write: arctan 2 = pi/2 - sum_(k=0)^oo (-1)^k 1/(2^(2k+1)(2k+1)) arctan(2) is an angle in a …

2016年4月16日 · Consider the following two right angled triangles: Then: #{ (tan(alpha) = 2), (tan(beta) = 3) :}# Notice that: ...

2015年9月24日 · Prove that (arctan (1) + arctan (2) + arctan (3) = pi) Call artan (1) = x; arctan (2) = y; and arctan (3) = z Apply the trig identity: tan (a + b) = (tan a + tan b ...

2015年5月25日 · In this way: #arctan2+arctan3=alpha#. Let's take now the tangent of both members: #tan(arctan2+arctan3)=tanalpharArr#

2016年8月11日 · The reqd. value =(11sqrt5)/25. Let arcsin(3/5)=alpha, &, arctan2=beta; alpha, beta in (-pi/2,pi/2). Hence, by defn., sinalpha=3/5>0 so, alpha in (0,pi/2), and ...

2016年7月21日 · By using the formula for the tangent of a sum, we find that the given sum is just \pi/4. Let tan\theta_1=1/2, tan\theta_2=1/3.

2016年2月18日 · 62254 views around the world You can reuse this answer ...

2015年9月7日 · Let alpha = arctan(2), then, we require the value of sinalpha . now tan alpha = 2 => sinalpha = 2/sqrt5. tanalpha = 2 => y= 2a, x = 2a & r = sqrt (5a^2 ) = sqrt5 a sinalpha = 2a/ …

2016年6月10日 · Set x=arctan2 hence tanx=2 square both sides to get tan^2x=4=>tan^2x+1=5=>1/cos^2x=5 Hence cosx=1/sqrt5 or ...

2016年6月6日 · Let #y=arctan(x^2)#.. Then #tan(y)=x^2#.From here, differentiate both sides of the equation. Recall that the chain rule comes into effect on the left-hand side.