BFB is the successor to the third season IDFB. It premiered on November 3, 2017, with the release of "Getting Teardrop to Talk", and concluded on April 9, 2021, with the release of "Chapter Complete". A fifth season, known as Battle for …

Back2Battlefield offers post-Gamespy Battlefield 2 a place to register accounts, create platoons and stay connected to continue playing Battlefield 2

Turn your room into your own Clubhouse of Awesomeness with the all-new Ice Cube Ice Lamp from BFDI! Slap her, and she lights up. Built as a collapsible rubbery shell, she can be toggled on/off...

泰勒公式是 f(x)=f(x_0)+f'(x_0)(x-x_0)+\frac12f''(x_0)(x-x_0)^2+... 则 F(\frac{a+b}{2})=F(a)+F'(a)(\frac{a+b}{2}-a)+\frac12F''(\xi)(\frac{a+b}{2}-a)^2 , 即 …

我们希望 x=a 和 x=b 是辅助函数的两个零点，只需再找出一个区间 (a,b) 内辅助函数的零点即可。 由于题目给出了一个可疑点 x=c ，因此我们非常希望这个点就是辅助函数的另一个零点。 即 f (c)-\frac {f (c) (c^ {2}+kc+m)} { (c-a) (c-b)}=0.

那么在区间 (a,b) 内至少有一点 \zeta(a< \zeta< b) ，使等式 f(b)-f(a)=f'(\zeta)(b-a) 成立。 亦即 \frac{f(b)-f(a)}{(b-a)}=f'(\zeta). 例： 设函数 f(x) 在 [a,b] 连续，在 (a,b) 内可导， a>0 ， f(a)=f(b)=1 ， 证明：存在 \zeta 使得 \eta\in(a,b) ， [\frac{\eta}{\zeta}]^{n-1}=f(\zeta)+(\eta/\zeta)f'(\zeta).

The bottom two is a state of risk at eliminations which consists of the two contestants with the most elimination votes (or least save votes) at an elimination. Its purpose is to create a moment of suspense before revealing which contestant is safe and which is eliminated.

2011年12月4日 · Battlefield 2 invades the high-tech frontlines of modern warfare. The game brings the intensity and excitement of Battlefield 1942 into the modern era with enhanced team play and the latest, most technologically advanced vehicles and weapons systems available to man. A small modification for the Polish troops. With edited weapons.

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按照朗格朗日，一根红线可以得到一个 \[\xi \] ，即根据 \[\frac{{f(b) - f(a)}}{{b - a}} = f'(\xi )\] 得到。 那么两根红线应该能得到两个 \[\xi \] ，而且还是两个不同的 \[\xi \] 。