Bias is another word for the operating point-- a dc voltage or current about which the instantaneous value might vary. For example, you can say you applied a "6 V peak-peak AC signal biased at +1 V". In this case the range of the signal would be from -2 to +4 V.

2023年2月22日 · It becomes quite inaccurate in pulse current rectification in power supplies, and in low bias small-signal applications - e.g. try pushing 10μA through an 1N4001 and see what forward voltage you get :) The textbooks do everyone a disservice by not being clear in what range of applications this rule of thumb applies. E.g.

2014年3月21日 · Without a DC voltage, spontaneous polarization can happen freely. However, when a DC voltage is externally applied, spontaneous polarization is tied to the direction of the electric field in the dielectric, and independent reversal of spontaneous polarization is inhibited. As a result, the capacitance becomes lower than before applying the bias.

2011年3月3日 · The reverse voltage is the voltage drop across the diode if the voltage at the cathode is more positive than the voltage at the anode (if you connect + to the cathode). This is usually much higher than the forward voltage. As with forward voltage, a current will flow if the connected voltage exceeds this value. This is called a "breakdown".

When the voltage is 56Vrms, I get the following results ( the green is the signal at PWM pin1 and the yellow is at R6 -the AM demodulator- ) The voltage at pin 1 of the PWM IC (UC3526AN) have to be 1.4VDC bias with 1Vpp when te input voltage is 100Vpp but it is not. The following is the real measurements at pin 1. At about 20Vrms input

\$\begingroup\$ can somebody clear this confusion: let us assume the activation voltage of the transistor at base is 0.7 V , and assuming it can tolerate up to 20 volts in its base, and suppose my AC signal has pk-pk voltage 6 volts, can I use 13 volts as a bias voltage? because 13+6=19 v it is not going to destroy the device, and when negative ...

2022年1月12日 · No. Your circuit won't work close to the negative rail because the input transistors don't get enough bias voltage, but it can work close to the positive supply rail. The OP284 has rail-to-rail inputs and outputs. To handle signals close to the negative rail it has an inverted form of your circuit wired in parallel, with PNP input transistors.

2023年2月27日 · As voltage is a result of the incoming charge, I'ld say DC-bias likely affects the change in the voltage for constant current - and it looks like the voltage rises faster with constant current into the capacitor (drops faster when the Cap provides the energy), while a perfect Cap has linear voltage change for a constant current. \$\endgroup\$

If you take the supply voltage VCC and subtract the design voltage of the electret insert microphone then divide by the electret's current draw you get the bias resistor in k ohms . It looks something like this 5 volt - 2 volt -:- .5 = 6k resistance . Work it out for your device data .

The resistor on the output side of the AC coupling cap biases that side to the DC bias voltage. If your circuit already has a clean, low impedance DC bias voltage source, connect to that. Otherwise, you can use circuit #2 to generate the bias, like this: (The simulation takes a loong time to reach the DC bias value, though.