Question: Draw the Lewis structure of acetaldehyde (CH3CHO) and then choose the appropriate pair of molecular geometries of the two central atoms. Your answer. choice is independent of the orientation of your drawn structure.

ch' + ch3cho → ch4 + ch,co. CH,CO. → CH' + CO 2 CHS → CH3CH3 k initiation k2 propagation k3 propagation termination Verify the rate law and define k in terms of the elementary steps in the above mechanism.

CH3CHO(g) 4CH + CO(g) Enter a number to 1 decimal place. Question 5 2 pts Acetaldehyde, CH3CHO, undergoes gas phase thermal decomposition to methane and carbon monoxide. The rate-law expression is rate = k[CH3CHO]?, and k-6.8 x 10 L/mol.hr) at 527°C. What is the half-life of CH,CHO if 0.57 mole is injected into a 5.8 L vessel at 527°C?

The thermal decomposition of acetaldehyde, CH3CHO --> CH4 + CO, is a second-order reaction. The rate constant is 1.55x10-4 M-1s-1 at 25oC. If the initial concentration of CH3CHO is 0.250M. What will the concentration be after 2.50 hours?

The decomposition of acetaldehyde, CH3CHO, in the presence of iodine is thought to occur by the following twostep mechanism. Step1: CH3CHO(g)+I2( g)→CH3l(g)+HI(g)+CO(g) Step2: CH3l(g)+HI(g)→CH4( g)+I2( g) Identify what is the catalyst used in this reaction.

Answer to The reaction of CH3CH2MgBr with CH3CHO gives: Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.

Question The organic compound CH3 CHO decomposes by the second-order reaction CH3CHO + CH4 + CO. If [CH3 CHO] = 0.551 mol/L at t = 0.00 seconds and [CH3 CHO] = 0.523 mol/L at t = 3600. seconds, what is the rate constant k of the reaction? Your answer should have 3 significant figures (report your answer in scientific notation).

Answer to In the drawing of acetaldehyde, CH3CHO, the

Acetaldehyde, CH3CHO, undergoes gas phase thermal decomposition to methane and carbon monoxide. If 0.72 mole is injected into a 1.0 L vessel at 527°C, how many moles remain after 433 hours? The rate-law expression is Rate = k[CH3CHO]2, and k = 4x 10-3L/(mol.hr) at 527°C. Enter a number to 4 decimal places.

Acetaldehyde, CH3CHO, undergoes gas phase thermal decomposition to methane and carbon monoxide. The rate-law expression is rate = k[CH3CHO], and k = 5.5 x 10-3 L/(mol.hr) at 527°C. What is the half-life of CH3CHO if 0.45 mole is injected into a 1.5 L vessel at 527°C? Enter a number to 0 decimal places.