CH3I + Na = CH3 + NaI is a Double Displacement (Metathesis) reaction where one mole of Methyl Iodide [CH 3 I] and one mole of Sodium [Na] react to form one mole of Methyl [CH 3] …

CH3I + Na = C2H6 + NaI is a Double Displacement (Metathesis) reaction where two moles of Methyl Iodide [CH 3 I] and two moles of Sodium [Na] react to form one mole of Ethane [C 2 H …

2010年8月3日 · CH3I，是1°卤代烃，其最重要的反应就是SN2亲核取代反应。 I-是一个很好的离去基团，因此CH3I可以和各种亲核试剂反应。 即亲核试剂Nu-进攻C原子与I原子离去同时发生， …

单位：摩尔质量 - g / mol，质量 - g。 让我们使用检验方法来平衡这个方程。 对于每个元素，我们检查方程两边的原子数量是否平衡。 Na 已平衡: 试剂中有 1 个原子，产品中有 1 个原子。 O …

Na is balanced: 1 atom in reagents and 1 atom in products. O is balanced: 1 atom in reagents and 1 atom in products. H is balanced: 4 atoms in reagents and 4 atoms in products. Let's balance …

CH3I + NaOH = NaI + CH3OH is a Double Displacement (Metathesis) reaction where one mole of Methyl Iodide [CH 3 I] and one mole of Sodium Hydroxide [NaOH] react to form one mole of …

2 CH3I + 2 Na → C2H6 + 2 NaI - Balanced equation | Chemical Equations online! This is an oxidation-reduction (redox) reaction: CH3I is an oxidizing agent, Na is a reducing agent.

Na is balanced: 1 atom in reagents and 1 atom in products. H is not balanced: 5 atoms in reagents and 4 atoms in products. In order to balance H on both sides we:

CH3I + CH3ONa = CH3OCH3 + NaI is a Double Displacement (Metathesis) reaction where one mole of Methyl Iodide [CH 3 I] and one mole of Sodium Methoxide [CH 3 ONa] react to form …

Our expert help has broken down your problem into an easy-to-learn solution you can count on. Show the mechanism, step-by-step, arrows, correct product and stereochemistry. There’s just …