
CH4 + 2O2 -> CO2 + 2H2O + heat If 5 mole of methane (CH4
Apr 25, 2018 · O_2 = 10 moles FIRST we make sure that the equation is balanced. Then we compare the coefficients of the compounds to find the molar ratios of reaction. CH_4 + 2O_2 -> CO_2 + 2H_2O is already balanced, so we only need to look at the ratio of methane and oxygen. CH_4 : O_2 = 1:2 or O_2 = 2xxCH_4 So, for 5 moles of …
#CH_4 +2O_2 ->CO_2 + 2H_2O# - Socratic
Mar 25, 2018 · Are there not "TWO moles" with respect to water? You have already written the stoichiometric equation that illustrates the combustion of methane gas... CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(l) And this tells you UNEQUIVOCALLY, that 16*g of methane gas reacts with 64*g of dioxygen gas to give 44*g of carbon dioxide gas, and 36*g of water. As always in a chemical reaction, MASS and charge are ...
What mass of oxygen is required to react completely with 1.
Mar 7, 2018 · #CH_4(g) + 2O_2(g) rarr CO_2(g) +2H_2O(l) + Delta#...and given the stoichiometry if I completely combust a #1.2*mol# quantity of methane, then CLEARLY I get a molar quantity of #1.2*mol# with respect to carbon dioxide...and a #2.4*mol# quantity of water....
How many moles of hydrogen are there in 25.3 g of methane, …
Dec 17, 2017 · The answer is that there are 6.32 mol of hydrogen in 25.3 g of CH_4. First step is to find the molar mass of methane: Carbon is 12, hydrogen is 1, so CH_4 is 12+4xx1=16 Find the number of moles of CH_4 in 25.3 g: n=m/M=25.3/16=1.58 mole In each mole of CH_4 there are 4 moles of hydrogen, so our answer is 4xx1.58=6.32 mol
How do you calculate the partial pressures of this problem?
Aug 13, 2016 · A mixture containing 2.53 g each of CH4(g), C2H4(g) and C4H10(g) is contained in a 1.50 L flask at a temperature of 25°C. (a) Calculate the partial pressure of each of the gases in the mixture. (b) Calculate the total pressure of the mixture. Answers in atmospheres.
A sample of gas contains 0.2000 mol of CH4 (g) and 0.4000 mol of …
Mar 8, 2018 · A sample of gas contains 0.2000 mol of CH4(g) and 0.4000 mol of O2(g) and occupies a volume of 20.3 L. The following reaction takes place: CH4(g) + 2O2(g)CO2(g) + 2H2O(g) Calculate the volume of the sample after the reaction takes place in liters?
Hydrogen gas (2.02 g/mol) can be produced from the reaction
Feb 25, 2018 · V = 1948.8L That is the "water shift" reaction. The balanced equation already given. With "excess" H_2O stipulated, we only need to convert the mass of the methane to the number of moles, then use the equation to find the number of moles of H_2 formed. With that value we use the ideal gas law to with the given temperature and pressure to find the actual volume of H_2 produced. 210g/16.05 = 13 ...
What is the maximum amount of CO2 which could be formed …
Mar 27, 2018 · What is the maximum amount of CO2 which could be formed from 14.49 g of CO and 0.13 mol of O2? Chemistry.
How do you write a balanced chemical equation for methane,
Aug 20, 2016 · How do you write a balanced chemical equation for methane, #CH_4# reacting with oxygen gas to produce water and Carbon Dioxide?
What is the VSEPR shape of the molecule CH4? | Socratic
Jul 1, 2014 · The methane molecule is tetrahedral. The central atom is carbon and there are four hydrogens attached at 109.5o angles to each other. Remember, molecules are 3D and the hydrogens are as far apart as possible in space so their electrons' repulsion is minimized.