2016年5月4日 · see below Use Property: cot^2x+1=csc^2x Left Side: = csc^2x-cot^2x =cot^2x+1-cot^2x =cot^2x-cot^2x + 1 =1 = Right Side

2016年12月14日 · How do you integrate #int csc^2(x/2) dx#? Calculus Introduction to Integration Integrals of Trigonometric Functions. 1 Answer

2018年4月13日 · #csc^2(x)=1/sin^2(x)# #d/dx[csc^2(x)]=d/dx[1/sin^2(x)]# #d/dx[1/sin^2(x)]=d/dx[[sin(x)]^{-2}]# let #u=sinx#. #d/dx[[sin(x)]^{-2}]=d/{du}[u^{-2}]d/dx[sinx]#

2018年4月25日 · Recall that d/dxcotx=-csc^2x Then, d/dx(-cotx)=csc^2x So, since we differentiate -cotx to get csc^2x, intcsc^2xdx=-cotx+C Calculus Science

2017年2月23日 · csc^2 x - 2csc - 2 = 0 Solve this quadratic equation for csc x. Since (a - b + c = 0), use shortcut. The 2 real roots are csc x = -1 and csc x = -c/a = 2 Convert csc = 1/(sin) to sin x, we get sin x = - 1 and sin x = 1/2 a. sin x = - 1 --> x = (3pi)/2 b.sin x = 1/2. Trig table and unit circle give: x = pi/6 and x = (5pi)/6 Answers for (0, 2pi ...

2018年1月3日 · -1 One of the fundamental identities is 1+cot^2(x) = csc^2(x). Starting with your given: cot^2(x)-csc^2(x) Replace csc^2(x) with 1+cot^2(x): cot^2(x)-(1+cot^2(x)) =cot^2(x)-1-cot^2(x)) =-1

2015年9月21日 · Simplify: csc^2 x - 1 Ans: cot^2 x 1/sin^2 x - 1 = (1 - sin^2 x)/sin^2 x = cos^2 x /sin^2 x = cot^2 x

2016年4月19日 · How do you find all the solutions for #2 \sin^2 \frac{x}{4}-3 \cos \frac{x}{4} = 0# over the

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2015年3月15日 · The antiderivative of csc^2x is -cotx+C. Why? Before trying anything 'fancy' (subsitutuion, parts, trig sub, misc sub, partial fractions, et c.) try 'staightaway' antidifferentiation. Do you know a finction whose derivative is csc^2x? Go through the list: d/(dx)(sinx)=cosx d/(dx)(cosx)=-sinx d/(dx)(tanx)=sec^2x Hang on! that's good! The derivative if a co function has a minus sign and ...