
How do you find the value of #csc ((pi)/2)#? - Socratic
2015年5月25日 · csc(theta) = 1/sin(theta) sin(pi/2) = 1 (this is a basic relation) rarr csc(pi/2) = 1
What does csc pi/2 equal? - Socratic
2015年9月7日 · csc(pi/2) = 1 csc(theta) = 1/sin(theta)color(white)("XXX")provided sin(theta)!=0 sin(pi/2) = 1 rarr csc(pi/2) = 1
How do you find the equivalent expression for #csc(x+pi/2)
2016年12月21日 · sec x Since sin (x + pi/2) = cos x (complementary arcs), there for: csc (x + pi/2) = 1/(sin (x + pi/2)) = 1/(cos x) = sec x
How do I find the value of csc pi/12? - Socratic
2015年8月12日 · Find csc (pi/12) Ans: 2/sqrt(2 - sqrt3) csc (pi/12) = 1/sin (pi/12). Find sin (pi/12) call sin (pi/12) = sin t cos 2t = cos ((2pi)/12) = cos ((pi)/6) = sqrt3/2. Use trig identity: cos 2t = …
Proving Identities - Trigonometry - Socratic
The best videos and questions to learn about Proving Identities. Get smarter on Socratic.
How do you find the value of #csc (pi/3)#? - Socratic
2018年6月21日 · How do you find the value of #csc (pi/3)#? Trigonometry Right Triangles Trigonometric Functions of Any Angle.
How do you find the value of #csc ((pi)/4)#? - Socratic
2015年5月22日 · csc (pi/4) = 1/sin(pi/4) Trig conversion table gives: sin ((pi)/4) = (sqrt2)/2 , then: csc (pi/4) = 2/(sqrt2) = sqrt2
Fundamental Identities - Trigonometry - Socratic
"The fundamental trigonometric identities" are the basic identities: •The reciprocal identities •The pythagorean identities
How do you find the other trigonometric functions given csc(pi/2 …
2017年2月28日 · We should first expand the parentheses. Recall that cscx = 1/sinx: 1/sin(pi/2- theta) = 9 Expand using the identity sin(A - B) = sinAcosB - sinBcosA. 1/(sin(pi/2)costheta - …
How do you graph #y=2csc2(x+pi)#? - Socratic
2018年6月24日 · As below. y = 2 csc (2x + 2 pi) Standard form of cosecant function is y = A csc(Bx - C) + D A = 2, B = 2 ...