Watch as the equilibrium between two different coloured cobalt species is disturbed, accompanied by a colour change predicted by Le Chatelier’s principle. The two different coloured Co (II) complex ions, [Co (H 2 O) 6] 2+ and [CoCl 4] 2-, exist together in equilibrium in solution in the presence of chloride ions:

Co(H 2 O) 6 2+ is formed by dissolving CoCl 2 *H 2 O in water. The first sample of the solution is heated to boiling. The first sample now contains a hot CoCl 4 2-solution. AgNO 3 is added to produce Co(H 2 O) 6 2+ again. A second sample is used as a reference. HCl is added to a third sample at room temperature.

2017年8月15日 · Cl+为弱场配体，故 [Co (Cl)4]^2- 应该是外轨型配离子，Co2+价层电子排布为sp2d3。 而Co2+的电子排布是3d7，即d轨道共7个电子，杂化后d轨道能级分裂形成3个未成对电子，即可确定t2g规定排5个电子（有一个单电子），eg排2个单电子. 在氯化钴溶液中，四氯合钴（Ⅱ）离子与六水合钴（Ⅱ）离子间存在如下平衡： [CoCl4]2-+6H2O⇌ [Co（H2O）6]2++4Cl-加水后，溶液中离子浓度减小，导致平衡向右移动。 [Co (Cl)4]^2- [四氯合钴（II）配离子]的d层 …

On the front cover, the pink colour in the test tube comes from cobalt(II) ions in water, Co(H 2 O) 6 2+. The blue colour is the result of cobalt chloride complex ions (CoCl 4 2–) in less dense acetone. This classic Le Châtelier’s Principle lab explores the reversible chemical reaction: Co(H 2 O) 6 2+ + 4Cl – + heat --> CoCl 4 2– + 6H 2 O

CoCl4 2- hybridizationCobalt tetrachloride [CoCl4]2- ion - Structure - hybridization - color - leChatelier principle, magnetic and electronic properties - Ad...

Two different colored cobalt(II) complexes exist in equilibrium, [Co(H 2 O) 6] 2+ (pink) and [CoCl 4] 2- (blue). This equilibrium may be disturbed by changing temperature - when placed in a cold bath, the solution will turn pink, on a hot plate, the solution will turn blue.

[CoCl 4] 2- (tetrahedral). How useful was this page? Click on a star to rate it! Average rating 2.5 / 5. Vote count: 24.

Examples of tetrahedal ions and molecules are [CoCl 4] 2-, [MnCl 4] 2-, and TiX 4 (X = halogen). Tetrahedral coordination is also observed in some oxo-anions such as [FeO 4] 4-, which exists as discrete anions in the salts Na 4 FeO 4 and Sr 2 FeO 4, and in …

2007年12月28日 · 氯化钴溶液中存在下列平衡：[cocl4]2-+6h2o [co（h2o）6]2++4cl-，向氯化钴稀溶液中加入一定量的浓盐酸，溶液中的氯离子浓度增大，平衡左移，co（h2o）6]2+溶液中显粉红色，[cocl4]2-溶液显蓝色，则溶液颜色变化为：由粉红色变为蓝色，

现将CoCl2溶于水，加入浓盐酸后，溶液由粉红色变为蓝色，存在以下平衡：[Co(H2O)6]2++4Cl−⇌[CoCl4]2−+6H2O Δ H，用该溶液做实验，溶液的颜色变化如下：以下结论和解释正确的是( ) A.等物质的量的[Co(H2O)6]2+和[CoCl4]2−中 σ 键数之比为3:2 B.由实验①可推知ΔH<0 C.实验 ...