Jun 28, 2015 · At #0# degrees, the angle intercepts the Unit Circle at the coordinate #(1,0)#. The coordinates are the trig values. The coordinates are the trig values. The x-coordinate is the #cos# value and the y-coordinate is the #sin# value.

Jun 1, 2018 · see below cos^(-1)0=arccos 0 What is the arc which cosine is zero?: two posibilities 90=pi/2 and 270=3pi/2 This is assuming that cos^(-1) is the inverse of cosine. There is no missunderstanding if use arccos instead of cos^(-1) Because cos^(-1) is also understud as 1/(cos)=sec which is different

From the "unit circle" cos(x)=0 when In terms of degrees: 90 and 270 degrees In terms of radians: (pi)/2 ...

May 15, 2016 · 90^o x= cos^-1(0) = 90^o Using the cosine graph, x could also = 270^o, 450^o, 810^o, -90^o, -270^o, -450^o, -810^o etc. Trigonometry Science

May 29, 2016 · Consider the rule C-A-S-T or All Slow Turtles Crawl for this type of problem. Both of these rules indicate in which quadrant the trigonometric function is positive. In all quadrants except the first, only 1 out of the three trigonometric functions are positive; the other two are negative. Quadrant 1: All are positive Quadrant 2: Sine is positive Quadrant 3: Tangent is …

Aug 18, 2015 · sin(0^o) = 0color(white)("XXXX")csc(0^o) "undefined" cos(0^o)=1color(white)("XXXX")sec(0^o)=1 tan(0^o)=0color(white)("XXXX")cot(0^o) "undefined" Using a triangle in standard position with the angle involved at the origin, the 6 basic trigonometric functions are defined as sin = "opposite"/"hypotenuse"color(white)("XXXX")csc ="hypotenuse ...

Oct 28, 2015 · cos^{-1}0=pi/2 graph{cosx [-7.855, 7.856, -3.93, 3.925]} cos^{-1} is an angle x, for which cos x=0. If you look at the graph of f(x)=cosx you see that cosx=0 for x=pi/2+kpi for any k in ZZ, so the smallest positive value is pi/2

Apr 1, 2016 · x=pi/2+kpi, k in ZZ In the trigonometric circle you will notice that cos(x)=0 corresponds to x=pi/2 and also x=-pi/2. Additionally to these all the angles that make a complete turn of the circle (2kpi) plus +-pi/2 correspond to cos(x)=0. So you have: x=+-pi/2+2kpi, k in ZZ If you try to see which are the first elements (from k =0, 1,2...of this series you will find that they …

Apr 5, 2018 · sin 2x + cos x = 0 2sin x.cos x + cos x = 0 cos x(2sin x + 1) = 0 either factor should be zero. a. cos x = 0 Unit circle gives 2 solutions -->

Feb 18, 2017 · x = pi/2, (3pi)/2, pi/4, (3pi)/4, (5pi)/4 and (7pi)/4 Note that cos3x can be rewritten as cos(2x + x). cosx + cos(2x + x) = 0 Now use cos(A + B) = cosAcosB - sinAsinB. cosx + cos2xcosx - sin2xsinx = 0 Apply cos2x = 2cos^2x -1 and sin2x = 2sinxcosx. cosx + (2cos^2x - 1)cosx - 2sinxcosx(sinx) = 0 cosx + 2cos^3x - cosx - 2sin^2xcosx = 0 Use sin^2x + cos^2x = 1: cosx + …