2018年6月1日 · see below cos^(-1)0=arccos 0 What is the arc which cosine is zero?: two posibilities 90=pi/2 and 270=3pi/2 This is assuming that cos^(-1) is the inverse of cosine. There is no missunderstanding if use arccos instead of cos^(-1) Because cos^(-1) is also understud as 1/(cos)=sec which is different

2015年10月28日 · cos^{-1}0=pi/2 graph{cosx [-7.855, 7.856, -3.93, 3.925]} cos^{-1} is an angle x, for which cos x=0. If you look at the graph of f(x)=cosx you see that cosx=0 for x=pi/2+kpi for any k in ZZ, so the smallest positive value is pi/2

2015年6月28日 · At #0# degrees, the angle intercepts the Unit Circle at the coordinate #(1,0)#. The coordinates are the trig values. The coordinates are the trig values. The x-coordinate is the #cos# value and the y-coordinate is the #sin# value.

2016年8月12日 · cos^-1 0=pi/2. We use the Defn. of cos^-1 : cos^-1x=theta, |x|<=1 iff costheta=x, theta in [0,pi] Since, cos(pi/2)=0, &, pi/2 in [0,pi], cos^-1 0=pi/2.

2018年5月18日 · Set cos^-1 0=x Hence cosx=0 For 0<=x<=2*pi the solutions are x=pi/2 and x=3*pi/2 The general solutions are x = ±π/2 + 2kπ where k is an integer

2015年9月17日 · Go through the cosines of special angles until you get to one whose cosine is 0 {: (bb"Special Angle (rad)", bb"Cosine"), (" "" "" "0," "1),(" "" "" "pi/6," "sqrt3/2 ...

2016年4月26日 · 2npi, n=0.+-1,+-2,+-3... The principal values of cos^(-1)(1) in [0,2pi] are 0 and 2pi So, the general value = .2npi, n=0.+-1,+-2,+-3..

2016年8月17日 · False due to a clash of conventions. If n > 1 is a positive integer, then: cos^n x = (cos x)^n This is a convenience of notation, to avoid having to use parentheses to distinguish, for example: (cos x)^2 and cos (x^2) By convention we can write: cos^2 x and cos x^2 respectively, without ambiguity. However, in the case of -1, we have a clash of notation. If f(x) is a function, then f^(-1)(x) is ...

2015年12月16日 · Since -0.8 is not a value you would find in a trigonometric ratio, which are: #sintheta#, #costheta#, #tantheta#, #csctheta#, #sectheta#, #cottheta#, you have to use a calculator to find the answer: #costheta=-0.8# #color(white)(xx)theta=cos^-1(-0.8)# #color(white)(xxx)~~143.13^@#

2017年1月1日 · cos^-1 (0.6)= 53.1° Note that cos^-1 does not mean 1/cos as we are used to in algebra. cos^-1 is the notation used for arc-cos. Cos 30° = 0.866 " "hArr" "cos^-1(0.866) = 30° In this case cos^-1 (0.60) is asking the question.. "Which angle has a Cos value of 0.60?" The only way to determine this is with a calculator or tables. Using a graph is possible, but not accurate enough. Depending on ...