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2016年8月6日 · Trig unit circle gives another arc x that has the same cos value --> #cos x = 1/2# --> #x = - pi/3# , or, #x = (5pi)/3# (co-terminal) Answers: #pi/3 and (5pi)/3#

Trigonometry mainly provides six functions for sine (sin), cosine (cos), and tangent (tan), also its reciprocal functions cosecant (csc), secant (sec), and cotangent (cot). These processes help in solving angle and distance related problems in both 2D and 3D surroundings.

\sin^ {2}x + \cos^ {2}x = 1. 1 + \tan^ {2} x = \sec^ {2}x. 1 + \cot^ {2}x = \csc^ {2}x. \tan {x} = \frac {\sin {x}} {\cos {x}} = \frac {\sec {x}} {\csc {x}} \cot {x} = \frac {\cos {x}} {\sin {x}} = \frac {\csc {x}} {\sec {x}}

Take the inverse cosine of both sides of the equation to extract x x from inside the cosine. Simplify the right side. Tap for more steps... The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from 2π 2 π to find the solution in the fourth quadrant. Simplify 2π− π 3 2 π - π 3.

#cos(cos^-1(1/2))#. let #cos^-1(1/2)=A :.cosA=1/2=cos(pi/3) :.A=pi/3 or cos^-1(1/2)=pi/3# So , #cos(cos^-1(1/2)) = cos (pi/3) =1/2# [Ans]

How do you evaluate \displaystyle{\cos{{\left({{\cos}^{{-{{1}}}}{\left(\frac{{1}}{{2}}\right)}}\right)}}} ?

2016年8月21日 · How do you find the exact value of cos−1(1 2)? Draw an equilateral triangle , cut it in half,: the ratio of the sides. is 1:2: √3. The angle whose cosine is 1 2 is 60 degrees.

2024年12月16日 · Ex 2.1, 5 Find the principal value of cos−1 (−1/2) Let y = cos−1 ((−1)/2) cos y = (−1)/2 cos y = cos (𝟐𝝅/𝟑) Since Range of cos−1 is [0 , 𝜋] Hence, the principal value is 𝟐𝝅/𝟑 Rough We know that cos 60° = 1/2 θ = 60° = 60° × 𝜋/180 = 𝜋/3 Since (−1)/2 is negative Pri

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