2015年5月13日 · On the trig unit circle: cos (540) = cos (180 + 360) = -1. sin 540 = sin (180 + 360) = 0. tan 540 = tan (180 + 360) = 0

2015年11月10日 · Find the 6 trig function values of 540 sin 540 = sin (180 + 360) = sin 180 = 0 cos 540 = cos 180 = - 1 tan (540) = sin/(cos) = 0 cot (540) = 1/(tan) = undefined sec ...

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2018年6月10日 · Using #sin(alpha-540^(circ))=sin(alpha)*cos(540^(circ))-cos(alpha)*sin(540^(circ))# since. #cos(540^(circ))=-1# #sin(540^(circ))=0#

2015年2月14日 · You may use the de Moivre's Theorem: z=r[cos(theta)+isin(theta)] =>z^n=r^n[cos(ntheta)+isin(ntheta)] In your case you get: z^4=2^4[cos(4*135°)+isin(4*135°)]= =16[cos(540°)+isin(540°)] (which is =-16 in rectangular form)

2016年4月25日 · theta = 75^0, 105^0 , 255^0,285^0 where theta<360 we know cos(180-30)=-sqrt3/2 or cos150=-sqrt3/2 :. 2 theta=150 or theta=75^0 Also cos(180+30)=-sqrt3/2 or cos210=-sqrt3/2 :. 2 theta=105 or theta=105^0 Similarly cos(540-30)=-sqrt3/2 or cos510=-sqrt3/2 :. 2 theta=255 or theta=255^0 Also cos(540+30)=-sqrt3/2 or cos570=-sqrt3/2 :. 2 theta=570 or theta=285^0[Ans]

2015年5月30日 · sec 600 = 1/cos 600. cos 600 = cos (240 + 360) = cos 240 = cos (60 + 180) = -cos 60 = -1/2 sec 600 = -2 sin 540 = sin (180 + 360) = sin 180 = 0 Answer: -2

2018年4月26日 · How do you convert complex numbers from standard form to polar form and vice versa?

2018年4月18日 · #cos (-a)# From the above sign table, #"Since 4 quadrants together form " 360^@#, # cos -(a) = cos (360 + (-a)) = cos (360-a)#.

2017年11月27日 · #cos x = -b/(2a) +- d/(2a) = - 7/-24 +- 1/24 = (7 +- 1)/24# #cos x = 8/24 = 1/3# #cos x = 6/24 = 1/4# a. #cos x = 1/3# Calculator and unit circle give 2 solutions: #x = +- 70^@53# b. #cos x = 1/4#--> #x = +- 75^@52# In the range (360, 540), there are only 2 answers: #x = 70.53 + 360 = 430^@53# #x = 75.52 + 360 = 435^@52#