
Find value of cos 55 +cos 125+ cos 300 - Brainly.in
2016年9月14日 · Hi , Here we use Signs of Trigonometric Ratios if θ lies in I , II , III , IV quandrants. According to the problem given, Cos 55 + Cos 125 + Cos 300 = Cos ( 90 - 35) + Cos ( 90 + 35 ) + Cos ( 270 + 30 ) = Sin 35 - Sin 35 + Sin 30 = Sin 30 = 1/2 I hope this helps you. ***
What is the value of cos 55⁰ - Brainly.in
2024年1月18日 · For cos 55 degrees, the angle 55° lies between 0° and 90° (First Quadrant). Since cosine function is positive in the first quadrant, thus cos 55° value = 0.5735764. . .
Prove: cos 24° + cos 55° + cos 125° + cos 204° + cos 300° = 1
2025年1月3日 · Answer: Step-by-step explanation:o prove that cos24∘ + cos 55 ∘ + cos 125 ∘ + cos 204 ∘ + cos 300 ∘ = 1 2 , we will use trigonometric identities and properties of cosine. 1. Rewrite the Cosine Terms: We can use the cosine angle subtraction and addition identities to rewrite some of the terms: cos 125 ∘ = cos ( 180 ∘ − 55 ∘ ...
Find the value of cos 55 degree - Brainly.in
2019年7月6日 · Click here 👆 to get an answer to your question ️ find the value of cos 55 degree
Sin 35°×cos 55°+cos 35°×sin 55°/cosec square 10°-- tan square 80°
2018年10月14日 · [tex]\dfrac {\sin 35\cos 55 +\cos 35\sin 55} {\csc^2 10-\tan^2 80}=1 [/tex]Step-by-step explanation:We have, [tex]\dfrac {\sin 35\cos 55 +\cos 35\sin 55} {\csc^2 10-\…
Prove that, Sin 55°- Cos 55° = √2 sin 10' - Brainly.in
2023年9月25日 · Click here 👆 to get an answer to your question ️ Prove that, Sin 55°- Cos 55° = √2 sin 10'
Simplify : cos 55° . cosec 35° - 1 - Brainly.in
2020年11月17日 · simplify : cos 55° . cosec 35° - 1 - 28808872
sin 35° cos 55° + cos 35º sin 55°cosec? 10°-tan80°ft - Brainly.in
2021年6月3日 · Sin 35° cos 55° + cos 35º sin 55° cosec? 10°-tan80°ft
cos 24° + cos 55° + cos 125° +cos 204° =-1012 - Brainly.in
Find an answer to your question cos 24° + cos 55° + cos 125° +cos 204° =-1012
Cos24+cos55+cos125+cos204+cos300= - Brainly.in
2019年11月27日 · Answer: Cos24 + cos55 + cos125 + cos204 + cos300 = ½ Step-by-step explanation: LHS =cos 24+cos 55+cos 125+cos 204+cos 300 = cos 24 +cos 55 +cos (180-55)+cos (180-24)+cos (270+30) = cos 24 +cos 55-cos …