2014年12月19日 · See explanation. This will be a long answer. So what you want to find is: int cos^6(x)dx There's a rule of thumb that you can remember: whenever you need to integrate an …

2018年5月23日 · LHS=sin^6x+cos^6x =(sin^2x)^3+(cos^2x)^3 Using formula a^3+b^3=(a+b)^3-3ab(a+b) =(sin^2x+cos^2x)^3+3sin^2xcos^2x(sin^2x+cos^2x) =1^3+3sin^2xcos^2x*1 =1 …

2016年1月30日 · int cos^6 x dx = 5/16 x + 1/4 sin 2x + 3/16 sin 4x -1/48 sin^3 2x int cos^6x dx We can rewrite this function as; int (cos^2x)^3dx Now we can rewrite cos^2 x using the half angle …

2015年8月5日 · Your cos function will oscillate between +1 and -1 and complete an entire oscillation, say, between zero and pi/3=1.05. Graphically you can see this by plotting your cos: …

2018年7月29日 · int cos^6x dx = ( 8cos^5x sinx +10 cos^3x sinx +15cosxsinx+15x)/48+C Write the integrand as: cos^6x = cos^5x * cosx So: int cos^6x dx = int cos^5x * cosx dx Integrate by …

2017年1月3日 · Using identity #a^3-b^3=(a-b)(a^2+b^2-ab)#. #sin^6x−cos^6x# = #(sin^2x)^3-(cos^2x)^3# = #(sin^2x-cos^2x)((sin^2x)^2+(cos^2x)^2-sin^2xcos^2x)#

2016年6月20日 · Recall that #cos^2theta=(1+cos2theta)/2.# #:. cos^2(6x)=(1+cos12x)/2.# #:. intcos^2(6x)dx=int(1+cos12x)/2dx=(1/2){x+(sin12x)/12}+C.#

2018年6月6日 · pi/6; pi/4; pi/3; (3pi)/4; (+ (kpi)/2) cos 6x + cos 4x + cos 2x = 0 (1) Use trig identity: cos (a + b) = cos ((a + b)/2)cos ((a - b)/2) We have: cos 6x + cos 2x = 2cos 4xcos 2x Equation …

Frequency and period are related inversely. A period #P# is related to the frequency #f# # P = 1/f#. Something that repeats once per second has a period of 1 s.

2018年1月18日 · How do you find the derivative of #sin(cos(6x))#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 2 Answers